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Important Questions for Class 11 Maths Chapter 13 Limits and Derivatives are provided in the article. Limits and derivatives are the initial concepts in mathematics prior to calculus. A limit is defined as a value that a function approaches as the input and produces some value. It is used to define integrals, derivatives and continuity. Limit of a function is represented as:
f(n)=L
A derivative refers to the instantaneous rate of change of a function with respect to a variable. The process of finding derivatives is known as differentiation. It helps to investigate the nature of an amount moment by moment. The derivative of a function is represented as:
\(\frac{f(x+h)-f(x)}{h} \)
Very short answer questions [1 Mark Question]
Ques. Evaluate the function \(\frac{(x^2-9)}{x-3} \) . [CBSE 2016]
Ans. Here, the limit of the given function is in 00.
Now, by representing the numerator as the product of two terms, we get
\(\frac{(x+3)(x-3)}{x-3} \)
= 3 + 3
= 6
Ques. Evaluate the function \(\frac{sinsin ax}{bx} \). [CBSE IE 2015,2013]
Ans. \(\frac{sinsin ax}{bx} \)=\(\frac{sinsin ax}{ax} \) X \(\frac{a}{b} \)
= 1×\(\frac{a}{b} \) ? \(\frac{sinsinx}{x} \) =1
= ab
Ques. Find the derivative of 2x with respect to x.
Ans. Assume the given expression as y=2x
By differentiating on both sides with respect to x we get,
\(\frac{dy}{dx} \) = ddx(2x)
\(\frac{dy}{dx} \)= 2xlog log2
Ques. Find the derivative of \(\sqrt{sinsin2x} \) with respect to x.
Ans. By using the chain rule of differentiation the derivative of given function is expressed by,
=\(\frac{d}{dx} \)\(\sqrt{sinsin2x} \) = \(\frac{1}{2\sqrt{sinsin2x}} \) \(\frac{d}{dx} \)sin sin2x
= \(\frac{1}{2\sqrt{sinsin2x}} \)× 2cos cos2x
= \(\frac{coscos 2x}{\sqrt{coscos 2x}} \)
Ques. Evaluates the function \(\frac{x^n-a^n}{x-a} \)xn-anx-a [CBSE 2013]
Ans. By differentiating the numerator and denominator with respect to x, we get
\(\frac{x^n-a^n}{x-a} \) = \(\frac{nx^{n-1}}{1} \)
=nan-1
Ques. What is the derivative of \(\frac{2^x}{x} \)
Ans. By using the u/v formula of differentiating we get,

Ques. Find the value of \(\frac{dy}{dx} \) if the expression is y=esin x .
Ans. By differentiating the given expression both sides we get,
\(\frac{dy}{dx} \)= \(\frac{d}{dx} \)(esinsin x )
= esinsin x cos x
=cos x esin x .
Ques. Differentiate xsinsin x with respect to x. [CBSE IE 2019]
Ans. By using the chain rule of differentiation we get,
\(\frac{d}{dx} \)(xsin x) = x(\(\frac{d}{dx} \)(sin sin x) )+ sin sinx \(\frac{d}{dx} \)(x)
=x(cos cos x) + sin sinx(1)
=x cos cosx + sin sinx
Ques. Evaluate the expression \(\frac{x^2+1}{x+100} \)
Ans. By substituting x=1 in the expression we get,
\(\frac{x^2+1}{x+100} \) = \(\frac{1+1}{1+100} \)
=2/101
Ques. Evaluate the expression \(\frac{tantan{\pi}x}{x+2} \)
Ans. By using differentiating the numerator and denominator with respect to x we get,
\(\frac{tantan{\pi}x}{x+2} \) = \(\frac{{\pi}sec^2({\pi}x)}{1} \)
=πsec2(-2π)
=π
Ques. Find the derivative of expression 1+x+x2+x3+…+x50 for x=1.
Ans. By the power rule of differentiation we get,
f'(x)=1+2x+3x2+4x3+…+50x50
By substituting x=1 in the above derivative we get,
f'(1)=1+2+3+…+50
=50(50+1)/2
=25×51
=1275
Ques. If the limit value is \(\frac{x^7+a^7}{x+a} \) , then find the value of variable a.
Ans. By substituting x=a in the expression we get,
\(\frac{x^7+a^7}{x+a} \)=7
\(\frac{a^7+a^7}{a+a} \)=7
a6=7
⇒a=6√7
Also read:
| Chapter Related Topics | ||
|---|---|---|
| Tautology | L' Hospital Rule | Mathematical Logic |
Short answer questions [2 Marks Question]
Ques. Evaluate the expression [cosec x-cot x] .
Ans. By rewriting cosec x and cot x in terms of cos x and sin x we get,

=0
Ques. Find the derivative of expression x-3(5+3x).
Ans. By multiplying x-3 to each term we get,
\(\frac{d}{dx} \)x-3(5+3x)= \(\frac{d}{dx} \)[5x-3+3x-2]
Now, by differentiating the equation we get
\(\frac{d}{dx} \)x-3(5+3x)=-15x-4 - 6x-3
\(\frac{d}{dx} \)[5x-3+3x-2]= -\(\frac{15}{x^2} \)-\(\frac{6}{x^3} \)
Ques. Find the derivative of f(x) = x3 using the first principle.
Ans. By definition of first principle,
f'x = \(\frac{f(x+h)-f(x)}{h} \)
By substituting f(x) = x3 in the above equation we get,
f'x = \(\frac{(x+h)^3-(x)^3}{h} \)
f'x = \(\frac{x^3+h^3+3xh(x+h)-x^3}{h} \)
f'x = h2+3x(x+h)
Substituting h=0 we get,
f'x=3x2
Ques. Find the derivative of \({e^{\sqrt{cotx}}} \).
Ans. By using the chain rule of differentiation, the derivative of the given expression is

Ques. Prove that the value of expression\(\frac{e^x-1}{x} \) is 1.
Ans.

By substituting the limit we get,
= 1 + 0
=1
Ques. Evaluate the function \(\frac{(1+cos 2x)}{(\pi-2x)^2} \) .
Ans.

Also read:
Long answer questions [3 Marks Question]
Ques. Evaluate the function \(\frac{(2x-3)(\sqrt{x}-1)}{2x^2+x-3} \) .
Ans. Represent the denominator as the product of two factors
\(\frac{(2x-3)(\sqrt{x}-1)}{2x^2+x-3} \) = \(\frac{(2x-3)(\sqrt{x}-1)}{(2x+3)(x-1)} \)
By using the formula for the expression x-1 in the denominator we get,
\(\frac{(2x-3)(\sqrt{x}-1)}{2x^2+x-3} \) = \(\frac{(2x-3)(\sqrt{x}-1)}{(2x+3)(\sqrt{x}-1)(\sqrt{x}+1)} \)
\(\frac{(2x-3)}{(2x+3)(\sqrt{x}+1)} \)
Now, substitute the value x=1 in the expression
=\(\frac{(2-3)}{(2+3)(1+1)} \)
=-1/10
Ques. If the expression is y= \(\frac{1-tantanx}{1+tantanx} \), then show that the derivative \(\frac{dy}{dx} \)= \(\frac{-2}{1+sinsin2x} \)
Ans. By differentiating the given expression on both sides we get,

Hence proved.
Ques. Let f(x) = {a+bx , x<1 4 , x=1 b-ax ,x>1 and f(x) = f(1) , then find the possible value of a and b. [IMP-2011]
Ans. We know that f(x) = limx→a-f(x)
By using the above equation for the given function at x=1 we get,
limx→1+ f(x) = f(1) = 4…………….(1)
limx→1- f(x) = f(1) = 4…………….(2)
For x>1 we have the function as f(x) = a+bx
Now, by using equation (1) we get,
limx→1+ f(x) = limx→1+(a+bx)
= a+b=4……………………(3)
Now, for x<1 we have the function as f(x) = b - ax
Now, by using equation (2) we get,
limx→a-f(x) = limx→a-(b-ax)
=a-b=4……………………(4)
Now, by adding equation (3) and (4) we get,
4+4 = (a+b) + (b-a)
8=2b
b=4
Similarly, the value of a=0
Ques. Find the derivative of f(x) = secsec x by the first principle. [IMP-2010]
Ans. The given function is f(x) = secsec x
We can write it as
f(x+h) =secsec(x+h)
By definition of first principle, we have,

Ques. Find the derivative of sin2x using product rule. [CBSE IE 2016]
Ans. Given function is y=sin2x
By writing it as product of two function we get,
⇒y=sin x × sin x
Differentiate on both sides using product rule.
\(\frac{dy}{dx} \) = \(\frac{d}{dx} \)(sin x × sin x )
=sinsinx\(\frac{d}{dx} \)sinsinx + sinx\(\frac{d}{dx} \)sinx
=sinxcoscos x + sin sin xcos x
=sin2x
Ques. Find the derivative of \(\frac{x^n-a^n}{x-a} \)
Ans. By differentiating using the quotient rule

Also read:
| Chapter Related Topics | ||
|---|---|---|
| Central limit theorem formula | Asymptote formula | Indeterminate forms |
Very long answer questions [5 Marks Question]
Ques. Differentiate x using first principle. [IMP-2012]
Ans. The given function is f(x) = x
We can write it as
f(x+h) = cosec (x+h)

Ques. Evaluate \(\frac{(a+h)^2sin(a+h)-a^2sina}{h} \)
Ans.

Ques. Find derivative of function [CBSE IE 2020]
- \(\frac{xsinsinx}{1+coscosx} \)
- (ax+b)(cx+d)2
Ans.

Ques. Differentiate the given functions [CBSE 2016,2018]
- \(\frac{a}{x^4}\) - \(\frac{b}{x^2}\) + cos x
- (x + cos x)(x – tan x)
Ans.

Also check:






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