NCERT Solutions For Class 11 Maths Chapter 8: Binomial Theorem

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NCERT Solutions for Class 11 Maths Chapter 8 Binomial Theorem are provided in the article below. Binomial theorem is the process of algebraically expanding power of sums of two or more binomials. Chapter 8 Binomial Theorem covers important concepts including Pascal’s Triangle and Binomial Expansion Formula.

Download: NCERT Solutions for Class 11 Mathematics Chapter 8 pdf


Class 11 Maths NCERT Solutions Chapter 8 Binomial Theorem

Class 11 Maths NCERT Solutions Chapter 8 Binomial Theorem are provided below:

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Also read: Binomial Theorem


Important Topics for Class 11 Maths NCERT Solutions Chapter 8 Binomial Theorem

Important Topics for Class 11 Maths NCERT Solutions Chapter 8 Binomial Theorem are elaborated below:

  • Pascal’s Triangle

Pascals triangle (Pascal's triangle) is an arrangement of binomial coefficients in triangular form. This triangle starts with 1 at the top, then 1s at both sides of the triangle until the end. 

Let’s understand Pascals Triangle Probability from the following table:

Number of Tosses/Row of Pascals Triangle Outcomes in Combinations Elements in Pascals Triangle
1 {H}
{T}
1, 1
2 {HH}
{HT TH}
{TT}
1, 2, 2001
3 {HHH}
{HHT, HTH, THH}
{HTT, THT, TTH}
{TTT}
1, 3, 3, 1
4 {HHHH}
{HHHT, HHTH, HTHH, THHH}
{HHTT, HTHT, HTTH, THHT, THTH, TTHH}
{HTTT, THTT, TTHT, TTTH}
{TTTT}
1, 4, 6, 4, 1
...etc... ... etc ... etc...
  • Binomial Expansion Formula

inomial expansion formulas are used to find the powers of the binomials which cannot be expanded using the algebraic identities. The binomial expansion formula involves binomial coefficients which are of the form:

\((_{k}^{n}) \) or \(n_{Ck}\)

It is calculated using the formula:

\(\frac{(_{k}^{n}) = n! }{[(n-k)!k!]}\)

NCERT Solutions For Class 11 Maths Chapter 8 Exercises:

The detailed solutions for all the NCERT Solutions for Chapter 8 Binomial Theorem under different exercises are as follows:

Also check:

Also check:

CBSE CLASS XII Related Questions

  • 1.

    Find:
    Let \(A=[a_{ij}]\) be a \(2\times2\) matrix whose elements are given by \[ a_{ij}=\frac{(2i-j)^2}{3} \] Find the transpose matrix \(A'\).

      • \(\begin{bmatrix} \frac{1}{3} & 3 \\ 0 & \frac{4}{3} \end{bmatrix}\)
      • \(\begin{bmatrix} \frac{1}{3} & 0 \\ 3 & \frac{4}{3} \end{bmatrix}\)
      • \(\begin{bmatrix} \frac{4}{3} & 3 \\ 1 & 0 \end{bmatrix}\)
      • \(\begin{bmatrix} \frac{4}{3} & 0 1 & \frac{3}{3} \end{bmatrix}\)

    • 2.

      Evaluate:
      \[ \int_{0}^{1} \frac{x \tan^{-1}x}{(1+x^2)^{3/2}}\,dx \]


        • 3.

          At a birthday party, children are being served orange juice in conical cups, as shown in the figure. 


          Each cup is 15 cm deep and has a radius 5 cm. The juice is being poured into this cup at a rate of 0·1 cm3/s.
          On the basis of the above information, answer the following questions :


            • 4.
              Using integration, find the area of the region bounded by the curve \( y = x|x| \), the x-axis, and the vertical lines \( x = -2 \) and \( x = 2 \).


                • 5.
                  Find:

                  The principal value of \[ \sec^{-1}(\sqrt{2})+2\csc^{-1}(-2) \] is:

                    • \(-\frac{\pi}{2}\)
                    • \(-\frac{\pi}{4}\)
                    • \(\frac{\pi}{4}\)
                    • \(\frac{\pi}{2}\)

                  • 6.

                    A carpenter needs to design a wooden box in the shape of a cuboid such that the sum of its length and breadth is 3 cm more than its height. Twice of its length, thrice of its breadth and its height add up to 10 cm. Its breadth added to 7 times its height is 1 cm less than 3 times its length. 

                      CBSE CLASS XII Previous Year Papers

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