NCERT Solutions for Class 11 Maths Chapter 8 Miscellaneous Exercises

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Class 11 Maths NCERT Solutions Chapter 8 Binomial Theorem Miscellaneous Exercises are based on following concepts:

  • Binomial Theorem for Positive Integral Indices
  • General and Middle Terms

Download PDF NCERT Solutions for Class 11 Maths Chapter 8 Binomial Theorem Miscellaneous Exercises 

Check out the solutions of Class 11 Maths NCERT solutions Chapter 8 Binomial Theorem Miscellaneous Exercises 

Read More: NCERT Solutions For Class 11 Maths Chapter 8 Binomial Theorem

Also check other Exercise Solutions of Class 11 Maths Chapter 8 Permutations and Combinations

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CBSE CLASS XII Related Questions

  • 1.
    Find:

    If \[ (3\hat{i}-2\hat{j}+5\hat{k})\times(4\hat{i}+p\hat{j}+q\hat{k})=\vec{0} \] then find the values of \(p\) and \(q\).

      • \(p = -\frac{2}{3}, \, q = \frac{5}{3}\)
      • \(p = -\frac{8}{3}, \, q = \frac{20}{3}\)
      • \(p = \frac{20}{3}, \, q = -\frac{8}{3}\)
      • \(p = 0, \, q = 0\)

    • 2.

      An NGO organises a charity event in which they decide to distribute woollen caps to protect children from winter. The caps to be distributed are in three separate boxes, Box I has 30 red caps, Box II has 20 red and 10 green caps, and Box III has 30 green caps. The probability that a Box i is selected and a cap picked out is i/6, where i = 1, 2, 3.  
      Based on the above information, answer the following questions :


        • 3.
          A relation $R$ on set $A=\{1,2,3\}$ defined as $R=\{(1,2),(2,1),(2,2)\}$ is

            • Reflexive only
            • Reflexive and Transitive
            • Symmetric and Transitive
            • Symmetric only

          • 4.
            If \( xy = e^{x - y} \), then find \( \frac{dy}{dx} \).


              • 5.

                Evaluate:
                \[ \int_{0}^{1} \frac{x \tan^{-1}x}{(1+x^2)^{3/2}}\,dx \]


                  • 6.
                    Find the vector and cartesian equations of the line passing through the point of intersection of the lines \( \vec{r} = (\hat{i} + \hat{j} - \hat{k}) + \lambda(3\hat{i} - \hat{j}) \) and \( \vec{r} = (4\hat{i} - \hat{k}) + \mu(2\hat{i} + 3\hat{k}) \) and parallel to the line \( \frac{x - 1}{-2} = \frac{7 - y}{-3} = z \).

                      CBSE CLASS XII Previous Year Papers

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