NCERT Solutions for Class 11 Maths Chapter 8 Exercise 8.2

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Class 11 Maths NCERT Solutions Chapter 8 Binomial Theorem Exercise 8.2 is based on General and Middle Terms.

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Check out the solutions of Class 11 Maths NCERT solutions Chapter 8 Binomial Theorem Exercise 8.2

Read More: NCERT Solutions For Class 11 Maths Chapter 8 Binomial Theorem

Also check other Exercise Solutions of Class 11 Maths Chapter 8 Permutations and Combinations

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Important Chapter Related Links
Perfect Square Binomial Formula	Algebra	Real-Valued Function
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CBSE CLASS XII Related Questions

1.
An NGO organises a charity event in which they decide to distribute woollen caps to protect children from winter. The caps to be distributed are in three separate boxes, Box I has 30 red caps, Box II has 20 red and 10 green caps, and Box III has 30 green caps. The probability that a Box i is selected and a cap picked out is i/6, where i = 1, 2, 3.
Based on the above information, answer the following questions :
2.
A relation $R$ on set $A=\{1,2,3\}$ defined as $R=\{(1,2),(2,1),(2,2)\}$ is
- Reflexive only
- Reflexive and Transitive
- Symmetric and Transitive
- Symmetric only
View Solution
3.
A carpenter needs to design a wooden box in the shape of a cuboid such that the sum of its length and breadth is 3 cm more than its height. Twice of its length, thrice of its breadth and its height add up to 10 cm. Its breadth added to 7 times its height is 1 cm less than 3 times its length.
4.
Find the vector and cartesian equations of the line passing through the point of intersection of the lines \( \vec{r} = (\hat{i} + \hat{j} - \hat{k}) + \lambda(3\hat{i} - \hat{j}) \) and \( \vec{r} = (4\hat{i} - \hat{k}) + \mu(2\hat{i} + 3\hat{k}) \) and parallel to the line \( \frac{x - 1}{-2} = \frac{7 - y}{-3} = z \).
View Solution
5.
If \( xy = e^{x - y} \), then find \( \frac{dy}{dx} \).
View Solution
6.
Find:

The shortest distance between the lines: \[ \vec{r}=(4+\lambda)\hat{i}+(2\lambda-1)\hat{j}-3\lambda\hat{k} \] and \[ \vec{r}=(1+2\mu)\hat{i}+(4\mu-1)\hat{j}+(2-5\mu)\hat{k} \]
View Solution

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