NCERT Solutions for class 11 Physics Chapter 9: Mechanical properties of solids

NCERT Solutions for Class 11 Physics Chapter 9: Mechanical Properties of Solids are provided in this article below. Mechanical properties of solids define the various characteristics of solids such as their resistance to deformation and their strength. 

Chapter 9 Mechanical Properties of Solids belongs to Unit 7 Properties of Bulk Matter. Unit 7 along with Unit 8 Thermodynamics and Unit 9 Behaviour of Perfect Gases and Kinetic Theory of Gases has a weightage of 20 marks in the Class 11 Examination. The Class 11 NCERT Solutions for Mechanical Properties of Solids discusses concepts such as Elastic behaviour of solids, Hooke’s law, and the Stress-strain curve.

Download PDF: NCERT Solutions for Class 11 Physics Chapter 9


NCERT Solutions for Class 11 Physics Chapter 9

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Class 11 Physics Chapter 9 – Concepts Covered

  • Stress is the ratio of the internal force F, produced when a substance is deformed, to the area A over which the force acts. 
\(Stress = {F \over A}\)
  • Strain is the ratio of the change in shape or size to the original shape or size. It is just a number and has no dimensions.
Strain is of 3 types – Longitudinal strain, Volumetric strain, and Shear strain
  • As per Hooke’s law, the ratio of stress to the corresponding strain produced within elastic limits is a constant. This constant is known as the modulus of elasticity. 
\(F_s = -kx\)
  • For a solid, in wire or a thin rod form, Young’s modulus of elasticity is defined as the ratio of longitudinal stress to longitudinal strain within the elastic limit. 

Young's Modulus

  • Poisson’s Ratio – The ratio of change in diameter (ΔD) to the original diameter (D) is known as lateral strain. The ratio of change in length (Δl) to the original length (l) is known as longitudinal strain. The ratio of lateral strain to the longitudinal strain is called Poisson’s ratio.
\(Poisson's\ Ratio\ = {Lateral\ strain \over Longitudinal\ Strain}\)

CBSE CLASS XII Related Questions

  • 1.
    A wire of length \(L\) is bent round into (i) a square coil having \(N\) turns and (ii) a circular coil having \(N\) turns. The coil in both cases is free to turn about a vertical axis coinciding with the plane of the coil, in a uniform, horizontal magnetic field and carry the same currents. Find the ratio of the maximum value of the torque acting on the square coil to that on the circular coil.


      • 2.
        Draw the plot of potential energy of a pair of nucleons as a function of their separation. Write two important conclusions that can be drawn from this plot.


          • 3.
            Consider the nuclear reaction \( X \to Y + Z \). Let \( M_x \), \( M_y \), and \( M_z \) be the masses of the three nuclei X, Y, and Z respectively. Then which of the following relations hold true?

              • \( (M_x - M_z)<M_y \)
              • \( (M_x - M_y)<M_z \)
              • \( M_x>(M_y + M_z) \)
              • \( M_x<(M_y + M_z) \)

            • 4.
              In a region, the electric potential varies as \(V = 10 - 50x\), where \(V\) is in volts and \(x\) is in meters. The electric field in the region is

                • \(10\ \text{N/C}\) along \(+x\)
                • \(10\ \text{N/C}\) along \(-x\)
                • \(50\ \text{N/C}\) along \(+x\)
                • \(50\ \text{N/C}\) along \(-x\)

              • 5.

                A rectangular loop of size 5 cm $\times$ 8 cm is lying in the $x$-$y$ plane in a uniform magnetic field $\vec{B} = (2.0\ \text{T})\hat{k}$. The total magnetic flux linked with the loop is:

                  • 80 Wb
                  • 16 Wb
                  • \(8 \times 10^{-2}\) Wb
                  • \(8 \times 10^{-3}\) Wb

                • 6.
                  Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

                    • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (\hat{i} - \hat{j})\)
                    • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (-\hat{i} - \hat{j})\)
                    • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (\hat{i} - \hat{j})\)
                    • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (-\hat{i} - \hat{j})\)
                  CBSE CLASS XII Previous Year Papers

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