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NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square Roots Exercise 6.2 is covered in this article. The exercise has questions on finding squares of numbers and determining the Pythagoras Triplets
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Examples From Chapter 6 Squares and Square Roots
| Ex.1 Simplify √125 X √320 Soln: Ex.2 Determine the smallest whole number with which 252 should be divided to get a perfect square. Find the square root of the number obtained. Soln: The prime factorization of 252 is 2 × 2 × 3 × 3 × 7 Therefore, prime factor 7 has no pair. So, when we divide 252 by 7, we get
252 ÷ 7 = 2 × 2 × 3 × 3 Thus each prime factor now has a pair. Therefore, 252 ÷ 7 = 36 is a perfect square. Thus, the required smallest number is 7. Hence, √36 = 2 × 3 = 6. |
Read More:
| Class 8 Chapter 6 Squares and Square Roots | ||
|---|---|---|
| Finding Square Roots | Number System | Sum of Squares |
| Long Division Method | Quotient | Value of log 1 to 10 |
| Prime Numbers | Root Mean Square | Nature of Roots of Quadratic Equation |
Also Check:
| CBSE Class 8 Maths Study Guide | ||
|---|---|---|
| Maths MCQs | Maths Study Notes | Maths Formula |
| NCERT Solutions for Class 8 Maths | Difference Between in Maths | Number System |
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