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NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square Roots Exercise 6.3 is covered in this article. This exercise mainly consists of problems to find square roots by repeated subtraction method, and Prime Factorization method.
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Examples From Chapter 6 Squares and Square Roots
| Ex. 1 Find the least number which when subtracted from 402 gives a perfect square. Find the square root of the number so obtained. Soln: This shows that 202 is less than 402 by 2. Therefore, when we subtract the remainder from the number, it is a perfect square. So, the least required number is 2. Therefore,
the required perfect square is (402 – 2) = 400. Hence, √400=20 Ex.2 By what number should 14700 be divided to obtain a perfect square? Find the square root of the perfect square thus obtained. Soln: 14700 =( 5× 5 × 2 × 2 × 7 × 7 × 3) = (5× 5) × (2 × 2) × (7 × 7) × 3 The factor 3 does not have a pair. ∴ The given number is to be divided by 3. 14700 ÷ 3 = 4900 √4900 = 70 |
Read More:
| Class 8 Chapter 6 Squares and Square Roots | ||
|---|---|---|
| Finding Square Roots | Number System | Sum of Squares |
| Long Division Method | Quotient | Value of log 1 to 10 |
| Prime Numbers | Root Mean Square | Nature of Roots of Quadratic Equation |
Also Check:
| CBSE Class 8 Maths Study Guide | ||
|---|---|---|
| Maths MCQs | Maths Study Notes | Maths Formula |
| NCERT Solutions for Class 8 Maths | Difference Between in Maths | Number System |
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