NCERT Solutions for Class 9 Maths Chapter 12: Heron's Formula

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The NCERT Solutions for Class 9 Maths chapter 12 Heron’s Formula are included in this article. Heron’s Formula is widely used to determine the area of different triangles, such as equilateral, isosceles and scalene triangle. It also helps to determine the area of different polygons, such as a cuboid and cone.

Class 9 Maths Chapter 12 Heron’s Formula belong to Unit 5 Mensuration which has a weightage of 13 marks in the Class 9 Maths Examination. Class 9 Maths Chapter 12 has the following important concepts: 

  1. Volume of a Cuboid
  2. Volume of a Right Circular Cone
  3. Volume of a Sphere

Download: NCERT Solutions for Class 9 Mathematics Chapter 12 pdf


NCERT Solutions for Class 9 Maths Chapter 12

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Important Topics in Class 9 Maths Chapter 12 Heron’s Formula

Important Topics in Class 9 Maths Chapter 12 Heron’s Formula are elaborated below:

Volume of a Cuboid

The volume of a Cuboid can be defined as the total space its occupies in three-dimensional space. In geometry, a cuboid has a total of 6 rectangular faces. 

Example: Determine the volume of a cuboid which has length 60 cm, breadth 30 cm and height 8 cm.

Solution: As per the given equation,
Length = 90 cm
Breadth = 30 cm
And Height = 15 cm
As we already know the formula, we can say,
Volume of a Cuboid = l × b × h (cubic units)
= (60 × 30 × 8) cm3
= 14,400 cm3

Volume of Right Circular Cone

The volume of a right circular cone can be expressed as its area or capacity of a cone.

Example: Determine the volume of a conical figure that has a radius of 9 feet and a height of 14 feet.

Solution: As per the given equation,
r = 9 feet
h = 14 feet
The volume of the conical figure is = 1/3 r²h 
= ? * 3.14 * (9)² * 14
= 1186.92 cubic feet

Volume of a Sphere

The volume of a sphere refers to the total amount of space it occupies. The volume of a sphere is measured in cubic units, like m3, cm3, in3 and more. 

Example: Determine the volume of a sphere that has a radius of 5 cm.

Solution: As we already know the volume of a sphere, we can say,
V = 4/3 πr3
= (4/3) x 3.14 x 53
= (4/3) x 3.14 x 5 x 5 x 5
= 523.3 cm3


NCERT Solutions for Class 9 Maths Chapter 12 Exercises:

The detailed solutions for all the NCERT Solutions for Heron’s Formula under different exercises are:

Also check:

Also Read:

CBSE X Related Questions

  • 1.
    Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.


      • 2.
        Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$


          • 3.
            If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

              • $x^2 + 5x - 4$
              • $(x + 3) (-x + 8)$
              • $a(x^2 + 5x - 24)$
              • $x^2 - 24$

            • 4.
              A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.


                • 5.
                  Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.


                    • 6.
                      Two dice are rolled together. The probability of getting an outcome $(x, y)$ where $x \gt y$, is

                        • $\frac{5}{12}$
                        • $\frac{5}{6}$
                        • $1$
                        • $0$

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