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The NCERT Solutions for Class 9 Maths chapter 12 Heron’s Formula are included in this article. Heron’s Formula is widely used to determine the area of different triangles, such as equilateral, isosceles and scalene triangle. It also helps to determine the area of different polygons, such as a cuboid and cone.
Class 9 Maths Chapter 12 Heron’s Formula belong to Unit 5 Mensuration which has a weightage of 13 marks in the Class 9 Maths Examination. Class 9 Maths Chapter 12 has the following important concepts:
Download: NCERT Solutions for Class 9 Mathematics Chapter 12 pdf
NCERT Solutions for Class 9 Maths Chapter 12




















Important Topics in Class 9 Maths Chapter 12 Heron’s Formula
Important Topics in Class 9 Maths Chapter 12 Heron’s Formula are elaborated below:
Volume of a Cuboid
The volume of a Cuboid can be defined as the total space its occupies in three-dimensional space. In geometry, a cuboid has a total of 6 rectangular faces.
| Example: Determine the volume of a cuboid which has length 60 cm, breadth 30 cm and height 8 cm. Solution: As per the given equation, |
Volume of Right Circular Cone
The volume of a right circular cone can be expressed as its area or capacity of a cone.
| Example: Determine the volume of a conical figure that has a radius of 9 feet and a height of 14 feet. Solution: As per the given equation, |
Volume of a Sphere
The volume of a sphere refers to the total amount of space it occupies. The volume of a sphere is measured in cubic units, like m3, cm3, in3 and more.
| Example: Determine the volume of a sphere that has a radius of 5 cm. Solution: As we already know the volume of a sphere, we can say, |
NCERT Solutions for Class 9 Maths Chapter 12 Exercises:
The detailed solutions for all the NCERT Solutions for Heron’s Formula under different exercises are:
- NCERT Solutions for Class 9 Maths Chapter 12 Exercise 12.1 Solutions
- NCERT Solutions for Class 9 Maths Chapter 12 Exercise 12.2 Solutions
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