NCERT Solutions for Class 9 Maths Chapter 3 Coordinate Geometry Exercise 3.1 Solutions

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NCERT Solutions for Class 9 Maths Chapter 3 Coordinate Geometry Exercise 3.1 Solutions are based on the introduction of Coordinate Geometry.

Also check: Important MCQs on Coordinate Geometry

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Check out NCERT Solutions for Class 9 Maths Chapter 3 Exercise 3.1 Solutions

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Exercise Solutions of Class 9 Maths Chapter 3 Coordinate Geometry

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CBSE X Related Questions

  • 1.
    In the figure given above, \(\triangle ABC \sim \triangle XYZ\), then find the values of \(x\) and \(y\).


      • 2.
        \(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

          • \(\frac{21}{4} \text{ cm}\)
          • \(\frac{28}{3} \text{ cm}\)
          • \(\frac{12}{7} \text{ cm}\)
          • \(5.5 \text{ cm}\)

        • 3.
          If \(\alpha, \beta\) are the zeroes of the polynomial \(p(x) = x^2 - 3x - 1\), then find the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\).


            • 4.
              If the quadratic equation \(9x^2 + 8kx + 16 = 0\) has real and equal roots, then the value of k is

                • 3
                • –3
                • –4
                • \(\pm 3\)

              • 5.
                PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.


                  • 6.
                    In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.

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