NCERT Solutions for Class 9 Maths Chapter 3 Coordinate Geometry Exercise 3.3 Solutions

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NCERT Solutions for Class 9 Maths Chapter 3 Coordinate Geometry Exercise 3.3 Solutions are based on plotting points on a plane if its coordinates are mentioned.

Also check: Important MCQs on Coordinate Geometry

Download PDF: NCERT Solutions for Class 9 Maths Chapter 3 Exercise 3.3 Solutions

Check out NCERT Solutions for Class 9 Maths Chapter 3 Exercise 3.3 Solutions

Read More: NCERT Solutions For Class 9 Maths Chapter 3 Coordinate Geometry

Exercise Solutions of Class 9 Maths Chapter 3 Coordinate Geometry

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CBSE X Related Questions

  • 1.
    The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

      • \((x + 2), (x - 5)\)
      • \((x + 5), (x - 2)\)
      • \((x + 1), (x - 5)\)
      • \((x - 1), (x + 2)\)

    • 2.
      If PQ and PR are tangents to the circle with centre O and radius 4 cm such that \(\angle QPR = 90^\circ\), then the length OP is

        • 4 cm
        • \(4\sqrt{2}\) cm
        • 8 cm
        • \(2\sqrt{2}\) cm

      • 3.
        If roots of the quadratic equation \(x^2 - k\sqrt{3}x + 2 = 0\) are real and equal, then value of k is

          • \(-2\)
          • \(\sqrt{\frac{8}{3}}\)
          • \(1\)
          • \(2\)

        • 4.
          The value of $\left(\frac{1}{2} \tan^2 45^\circ - \cos^2 60^\circ\right)$ is :

            • $0$
            • $-\frac{1}{2}$
            • $\frac{1}{4}$
            • $-\frac{1}{4}$

          • 5.
            In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

              • $6$
              • $4$
              • $\pm 4$
              • $3$

            • 6.
              For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

                • \(0\)
                • \(\frac{80}{81}\)
                • \(1\)
                • \(\frac{82}{80}\)

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