NCERT Solutions for Class 9 Maths Chapter 3 Coordinate Geometry Exercise 3.2 Solutions

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NCERT Solutions for Class 9 Maths Chapter 3 Coordinate Geometry Exercise 3.2 Solutions are based on the Cartesian System.

Also check: Important MCQs on Coordinate Geometry

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Check out NCERT Solutions for Class 9 Maths Chapter 3 Exercise 3.2 Solutions

Read More: NCERT Solutions For Class 9 Maths Chapter 3 Coordinate Geometry

Exercise Solutions of Class 9 Maths Chapter 3 Coordinate Geometry

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CBSE X Related Questions

  • 1.
    If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

      • $x^2 + 5x - 4$
      • $(x + 3) (-x + 8)$
      • $a(x^2 + 5x - 24)$
      • $x^2 - 24$

    • 2.
      The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :

        • $q - 9p$
        • $p - 9q$
        • $p + 9q$
        • $2p + 9q$

      • 3.
        If \(\alpha, \beta\) are the zeroes of the polynomial \(p(x) = x^2 - 3x - 1\), then find the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\).


          • 4.
            The HCF of 960 and 432 is :

              • 48
              • 54
              • 72
              • 36

            • 5.
              PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.


                • 6.
                  The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

                    • 0
                    • 1
                    • 3
                    • 2

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