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Poiseuille’s law formula states that the flow of a fluid depends on different variables such as the radius (r) and length of the tube (L), pressure gradient (∆P), and the viscosity of the fluid (η) as per their relationship.
- It is also known as Hagen–Poiseuille equation, Hagen–Poiseuille law, Poiseuille law or Poiseuille equation.
- The law determines the pressure drop in an incompressible fluid in laminar flow flowing through a long cylindrical pipe of the constant cross section.
- It was derived by Jean Léonard Marie Poiseuille in 1838 and Gotthilf Heinrich Ludwig Hagen.
- Poiseuille’s formula assumes that there is no acceleration of fluid in the pipe.
- It helps in designing heating, ventilation, and air conditioning systems.
- Poiseuille’s law Formula is represented as
Q = ΔPπr4 / 8ηl.
- where ∆P is the pressure gradient
- η is the viscosity
- l is the length of the tube
Key Terms: Poiseuille's Law Formula, Pressure Gradient, Viscosity, Resistance, Speed, Narrow Tube, Cylindrical Pipe, Poiseuille Formula Derivation
Poiseuille’s Law Formula
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Poiseuille Law Formula studied the streamlined flow of a liquid in capillary tubes. According to the equation the law concluded that the volume, V of the liquid flowing per second through a capillary tube is:
- Directly proportional to the difference of pressure, P between the two ends of the tube. i.e; V α P.
- Directly proportional to the fourth power of the radius, r of the capillary tube. i.e; V α r4.
- Inversely proportional to the coefficient of viscosity, η of the liquid. i.e; V α 1/η.
- Inversely proportional to the length, l of the capillary tube. i.e; V α 1/l.
Combining these factors, Poiseuille’s Formula can be given as
V α Pr4/ηl
Or
\( V = {KP r^4 \over η l}\)
- Where k = π/8, a constant of proportionality.
So, we get \( V = {\pi P r^4 \over 8η l}\)
- Where, p is the pressure difference across the two ends of the tube.
- r is the radius of the tube
- η is the coefficient of viscosity,
- l is the length of the tube
This equation is called Poiseuille’s equation, which consists of the following components.
Pressure Gradient (P)
Here the pressure differential between the two ends of the tube is defined by the fact that every fluid will always flow from the High-Pressure Area (P1) to the Low-Pressure Area (P2). The flow rate is calculated by P = P1 - P2.
Radius of the Narrow Tube (r)
The flow of liquid directly changed with the radius to the power four.
Viscosity (η)
The rate of flow of the fluid is inversely proportional to the viscosity of the fluid.
Length of the Narrow Tube (L)
The rate of flow of the fluid is inversely proportional to the length of the narrow tube.
Resistance (R)
The resistance is calculated by 8Ln/πr4 and hence the Poiseuille’s law is Q= ΔP*R
The video below explains this:
Poiseuille's Formula Detailed Video Explanation:
Solved Example of Poiseuille’s Law FormulaExample: Calculate the average speed of the blood when the blood flow through a large artery of radius 2.5 mm is found to be 20 cm long. The pressure across the ends of the artery is known as 380 Pa. Solution: Blood viscosity η = 0.0027 N .s/m2 l = 20 cm Radius = 2.5 mm The difference of pressure = 380 Pa (P1 – P2) The average speed is given by Q = ΔPπr4 / 8ηl Q = \((380 × 3.906 × 10-11 × 3.14) \over (8 × 0.0027 × 0.20)\) The average speed becomes 1.0789 m / s |
| Poiseuille’s Law Formula – Related Topics | ||
|---|---|---|
| Hydrostatic Pressure | Different Properties of Fluids | Fluid Flow |
| Pascal’s Law | Hydraulic Machines | Bernoulli’s principle |
| Venturi-meter | Stokes’ Law | Surface tension |
Derivation of Poiseuille’s Law Formula
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Poiseuille’s found that the volume of a liquid flowing through a capillary tube per second depends upon
- The pressure gradient (P/l) (i.e. the rate of change of pressure with length)
- The radius of the capillary tube, r
- Coefficient of the viscosity of the liquid, η
Poiseuille’s Law Formula
Therefore, V = K (P/l)a rb ηc …… (i)
Where K is proportionality constant.
- The dimension of V per second = [L3 T-1]
- The dimension of P/l = [M L-1 T-2] / [L] = [M L-2 T-2]
- The dimension of r = [L]
- The dimension of η = [M L-1 T-1]
Putting the dimensions of the quantities in Equation (i)
we get,
[L3 T-1] = [M L-2 T-2]a [L]b [M L-1 T-1]c
or
[M0 L3 T-1] = [Ma+c L-2a+b-c T2a-c]
- Applying the principle of homogeneity of dimensions
- we get,
- Powers of M, a+c = 0 ….......... (ii)
- Powers of L, -2a+b-c = 3 ….... (iii)
- Powers of T, -2a-c = -1 …....... (iv)
- Solving these three equations, we get a = 1, b = 4 and c = -1 and substituting the values of a, b and c in Equation (i)
- we get,
- V = K (P/l)1 (r)4η-1
- = K P r4/ η l
- The value of K is found experimentally to be π/8 and the above equation changes to
\( V = {\pi P r^4 \over 8η l}\)
- This equation is called Poiseuille’s equation or Poiseuille’s formula.
Example of Derivation of Poiseuille’s Law FormulaExample: The blood flow through a large artery of radius 1.5 mm is found to be 10 cm long. The pressure across the artery ends is 300 Pa, calculate the blood’s average speed. Solution: The blood viscosity η = 0.0027 N .s/m2 Radius = 1.5 mm l = 10 cm The difference of pressure = 300 Pa ( P1 – P2) The average speed is given by Q = ΔPπr4 / 8ηl Q = (300 × 3.906 × 10-11 × 3.14)/(8 × 0.0027 × 0.10) The average speed becomes 1.703 m / s |
Application of Poiseuille's Law Formula
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The applications of Poiseuille's formula can be given as:
- The Poiseuille law formula has been used vastly in the medical fields, especially since it helps us to understand the blood pressure of our body.
- It is used to predict the vascular resistance and flow rate of the intravenous fluid.
- The law is used to analyze the viscosity of various fluids, especially liquids used for chemical analysis, DNA testing, and fuel for automobile engines.
- It is used to analyze and design the internal combustion engine and gas turbines.
- The law helps determine the external flow rate of the motors used in heavy vehicles or equipment.
- The poiseuille law formula is used in designing space vehicles, spacecraft configurations, and astronaut equipment.
Limitations of Poiseuille Law Formula
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Poiseuille law has certain limitations when applied to circulating blood.
- Blood vessels are not rigid tubes and are quite distensible, so their size depends on the blood pressure within them as well as the contraction of smooth muscles in the vessel walls.
- Blood is a non-Newtonian fluid, and fluid viscosity is not constant.
- The flow is not steady but pulsatile in most parts of the vascular bed.
The assumptions of Poiseuille’s equation are
- A long rigid cylinder is used with a length much greater than the radius
- Fluid has constant viscosity and is incompressible
- Steady Laminar flow is not pulsatile and turbulent
- The fluid velocity at the edges of the tube is zero
Read Also:
| Mechanical Properties of Fluids – Related Topics | ||
|---|---|---|
| Surface Energy | Barometer | Unit of Pressure |
| Mechanical Properties of Fluids | Reynolds Number | Density |
| Buoyant Force | Fluid Friction | Critical Velocity |
| Value of R in atm | Derivation of Continuity Equation | Hydrostatic Paradox |
Things to Remember
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- Poiseuille's Law Formula is an easy way to take out the correct viscosity of the liquid that goes through a narrow tube.
- The equation uses the velocity of the fluid to calculate the pressure with which the liquid flows through the tube.
- The fourth power of the tube's radius is also a varying factor.
- One must keep in mind that there is an inverse proportionality between the velocity of the liquid and the length of the tube.
- It is also inversely proportional to the coefficient of viscosity.
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Sample Questions
Ques. Which of the following statements is NOT TRUE? (1 mark)
(A) As the depth in a liquid increases, the total pressure also increases
(B) The pressure in a liquid depends on its density
(C) The pressure at a certain depth in a pond will be greater than the pressure at the surface of the pond
(D) As the depth in a liquid increase, the total pressure decreases.
Ans. (D) As the depth in a liquid increases, the total pressure decreases.
Explanation - Liquid pressure drops as the depth of liquid increases. The height or depth of an item from the surface determines the pressure at a place in a fluid.
Ques. Which of the following statements is true as applied to the flow of an ideal incompressible fluid? (1 mark)
(A) Where the area of cross-section is small, the flow rate is large
(B) Where the area of cross-section is small, the flow rate is small
(C) Where the area of cross-section is small, velocity is small
(D) Where the area of cross-section is small, velocity is high.
Ans. (D) Where the area of cross-section is small, velocity is high.
Explanation - The rate of blood flow, or velocity, is inversely proportional to the total cross-sectional area of the blood arteries. The velocity of flow reduces as the total cross-sectional area of the tubes rises.
Ques. According to Poiseuille’s Law (as applied to the laminar flow of an incompressible viscous fluid)? (1 mark)
(A) Flow resistance is proportional to the fourth power of tube radius
(B) Rate of flow is inversely proportional to the fourth power of the tube radius
(C) A reduction in tube radius by a half decreases flow rate 1/16th of the original value
(D) None of the above is true.
Ans. (C) A reduction in tube radius by half decreases flow rate 1/16th of the original value.
Explanation - The radius is equal to half of the diameter. At constant pressure and temperature, if you double the length of the pipe while keeping the diameter constant, you'll get nearly half as much water through it in the same amount of time.
Ques. Let's assume that the blood flow rate is reduced to half its normal value. By what factor has the radius of the artery reduced? Neglect the turbulence and the answer can be in percentage also? (3 marks)
Ans. If all the factors are considered to be constant, the equation that is used is
Q1/r14 = Q2/r24
If the flow rate is reduced by half, put the value of final flow rate to be equal to half of the initial flow rate and develop the relationship between the radii under different flows.
Q1/r14 = Q1/ 2* r24
r24 / r14= 1/2
r2/r1 = (1/2)1/4
r2=0.841r1
Ques. For the flow of water in the tube, the velocity at the surface is ___________? (1 mark)
a) zero
b) equal to the velocity at 1/3 of diameter
c) equal to the velocity at 1/2 of diameter
d) equal to the velocity at centre
Ans. (a) zero
Explanation: Because of molecular attraction, the tube's surface is moist, generating a very thin coating of water that is immobile. As a result, the surface velocity is zero.
Ques. Name the units in which we measure Poiseuille's Law? (1 mark)
Ans. The units to measure Poiseuille’s Law are –
- (N/m²)s
- Pascal Second (Pa-s)
Ques. Write a short note on Poiseuille's? (3 marks)
Ans. Poiseuille's Law is an easy way to take out the correct viscosity of the liquid that goes through a narrow tube The equation uses the velocity of the fluid to calculate.
- One thing that varies directly during the application of this formula is the pressure with which the liquid flows through the tube.
- The fourth power of the tube's radius is also a varying factor.
- One must keep in mind that there is an inverse proportionality between the velocity of the liquid and the length of the tube.
- It is also inversely proportional to the coefficient of viscosity
Ques. What is the importance of Poiseuille's Law? (2 marks)
Ans. Poiseuille's Law Formula is used to describe the relationship that is there between the pressure, flow rate, and fluidic resistance. It is also used for the determination of pressure drop pertaining to a constant viscosity fluid This fluid basically exhibits the laminar flow that goes through a tight pipe
Ques. Where is Poiseuille's law used? (2 marks)
Ans. Hemodynamics is perhaps the most common application field where Poiseuille's law is used & This low is used to explain the reason behind the constricted capillaries leading to greater blood pressure since the volumetric flow rate is so sensitive to variations in cross-sectional area.
Ques. The blood flow through a large artery of a radius of 3.5mm is 30 cm long. The blood pressure across the artery ends is 200 Pascals. Determine the blood's average speed? (5 marks)
Ans. It is given that the change in the pressure is 380 Pascals, the radius is 2.5 mm and the length is 20 cm. The average viscosity of the blood is 0.0027 Ns/m2 . The formula used to calculate the average speed is
Q =ΔPπr4/8ηL
The blood viscosity η = 0.0027 Ns/m2
Radius = 3.5 mm
l = 30 cm
The difference of pressure = 200 Pa ( P1 – P2)
The average speed is given by
Q = ΔPπr4 / 8ηl
Q = (200 × 3.906 × 10-11 × 3.14)/(8 × 0.0027 × 0.30)
The average speed becomes 3.78 m/s
Ques. A liquid flows through a tube with a radius of 1 m and a length of 0.5 m. Determine the pressure across the tube ends if the flow of liquid is 10 m3/s. The liquid's viscosity is 0.132 Pa? (3 marks)
Ans. Given data:
Q = 10
r = 1
η= 0.132
l = 0.5.
Using the formula, Q = ΔPπr4 / 8ηl
10 = ΔP x 3.14 x 14 / 8 x 0.132 x 0.5
ΔP = 10 x 8 x 0.132 x 0.5 / 3.14 x 14
ΔP = 1.2 Pa
Ques. A liquid flows through a tube with a 200 Pa pressure gradient and a resistance of 200Pas/m3. Determine the volumetric flow rate? (2 marks)
Ans. Given data:
- ΔP = 100
- R = 200
- Using the formula, Q = ΔP/ R
- 200 / 200
- 1m3/s.
Ques. A liquid flows through a tube with a radius of 1 m and a length of 0.2 m. Determine the pressure across the tube ends if the flow of liquid is 20 m3/s. The liquid's viscosity is 0.12 Pa? (3 marks)
Ans. Given data:
Q = 20
r = 1
η= 0.12
l = 0.2.
Using the formula, Q = ΔPπr4 / 8ηl
20 = ΔP x 3.14 x 14 / 8 x 0.12 x 0.2
ΔP = 10 x 8 x 0.12 x 0.2 / 3.14 x 14
ΔP = 0.043 Pa
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