NCERT Solutions for Class 11 Maths Chapter 7 Exercise 7.3

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Class 11 Maths NCERT Solutions Chapter 7 Permutations and Combinations Exercise 7.3 is based on following concepts:

Derivation of the formula for nPr
Permutations when all the objects are not distinct objects

Download PDF NCERT Solutions for Class 11 Maths Chapter 7 Permutations and Combinations Exercise 7.3

Check out the solutions of Class 11 Maths NCERT solutions Chapter 7 Permutations and Combinations Exercise 7.3

Read More: NCERT Solutions For Class 11 Maths Chapter 7 Permutations and Combinations

Also check other Exercise Solutions of Class 11 Maths Chapter 7 Permutations and Combinations

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Combinatorics	Involute	Difference between Permutation and Combination

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CBSE CLASS XII Related Questions

1.
Check whether \[ f:\mathbb{R}-\{3\}\rightarrow\mathbb{R} \] defined as \[ f(x)=\frac{x-2}{x-3} \] is onto or not.
View Solution
2.
Assertion (A) : In an experiment of throwing an unbiased die, the probability of getting a prime number given that number appearing on the die being odd is \( \frac{2}{3} \).
Reason (R) : For any two events \( A \) and \( B \), \( P(A|B) = \frac{P(A \cup B)}{P(B)} \).
- Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true and Reason (R) is false.
- Assertion (A) is false and Reason (R) is true.
View Solution
3.
For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]
- local maximum value is 2
- local minimum value is \( -2 \)
- local maximum value is \( -2 \)
- local minimum value \( < \) local maximum value
View Solution
4.
Find: \[ \int \frac{x^2}{(x^2+9)(x^2+16)}\,dx \]
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5.
Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not.
View Solution
6.
If \[ B(\operatorname{adj} B)= \begin{bmatrix} \frac{1}{3} & 0 & 0\\ 0 & \frac{1}{3} & 0\\ 0 & 0 & \frac{1}{3} \end{bmatrix}, \] then the value of \[ \det(B^{-1}) \] is:
- \(\frac{1}{3}\)
- \(\frac{1}{9}\)
- \(3\)
- \(9\)
View Solution

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