NCERT Solutions For Class 11 Physics Chapter 11: Thermal Properties of Matter

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NCERT Solutions for Class 11 Physics Chapter 11 Thermal Properties of Matter are given in the article. The matter is the one due to which a matter exhibits heat conductivity or it is the property that decides the nature of the matter in the presence of heat. Thus, thermal properties are exhibited by objects when heat passes through them. Temperature is one of the physical properties of matter.

Class 11 Physics Chapter 11 Thermal Properties of Matter belongs to Unit 7 Properties of Bulk Matter which along with Unit 8 and Unit 9 has a weightage of 20 marks. NCERT Solutions for Chapter 11 Class 11 Physics covers concepts of specific heat capacityLatent heat formula, and Blackbody Radiation.

Download PDF: NCERT Solutions for Class 11 Physics Chapter 11


NCERT Solutions for Class 11 Physics Chapter 11


Class 11 Physics Chapter 11 – Concepts Covered

  • The thermal energy of a body is the quantity of heat that is required to raise the temperature of the whole body by a unit degree. If Q is the amount of heat that’s needed to produce a temperature change (Δt), then the thermal capacity of the substance is given as:
\(S = {Q \over \bigtriangleup t}\)
  • The Specific Heat Capacity of a substance is the amount of heat that is required to raise the temperature of a unit mass of a substance by 1° C. 
\(S = {1 \over m} {Q \over \bigtriangleup t}\)
From the law of energy conservation: Heat gained by one body = heat lost by the other
  • The Basic Heat Formula: The heat Q that is required to raise the temperature of a substance with mass m of specific heat capacity s through t degrees is given by

Q = m x S x t

  • Newton’s law of cooling states that the rate of loss of heat in a body is proportional to the difference in temperature of the body and its surroundings provided that the difference in temperature is small and is not more than 40° C.

\({dT \over dt} = -K(T-T_s)\)

The negative sign implies that as time passes, the temperature decreases.


CBSE CLASS XII Related Questions

  • 1.
    Four independent waves are expressed as \[ (i)\; y_1=A_1\sin\omega t, \] \[ (ii)\; y_2=A_2\sin 2\omega t, \] \[ (iii)\; y_3=A_3\cos\omega t, \] \[ (iv)\; y_4=A_4\sin\left(\omega t+\frac{\pi}{3}\right) \] The interference between two of these waves is possible in

      • (i) and (iii) only
      • (iii) and (iv) only
      • (i), (iii) and (iv) only
      • All of them

    • 2.
      Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

        • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
        • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
        • Assertion (A) is true, but Reason (R) is false.
        • Both Assertion (A) and Reason (R) are false.

      • 3.
        Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

          • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
          • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
          • Assertion (A) is true, but Reason (R) is false.
          • Both Assertion (A) and Reason (R) are false.

        • 4.
          What is displacement current (\( i_d \))? Considering the case of charging of a capacitor, show that \( i_d = \varepsilon_0 \frac{d\Phi_E}{dt} \). What is the value of \( i_d \) for a conductor across which a constant voltage is applied?


            • 5.
              The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

                • \( \frac{q}{4 \pi \epsilon_0 l^2} \) pointing along MA
                • \( \frac{q}{\pi \epsilon_0 l^2} \) pointing along AM
                • \( \frac{q}{2 \pi \epsilon_0 l^2} \) pointing along AM
                • Zero

              • 6.
                Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

                  CBSE CLASS XII Previous Year Papers

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