NCERT Solutions for class 11 Physics Chapter 15: Waves

NCERT Solutions for Class 11 Physics Chapter 15: Waves deals with the concepts of wave and wave motion. Wave motion is referred to as the energy and momentum movement from one point to another in a medium instead of actually transferring the substances between the places.

Class 11 Physics Chapter 15 Waves is a part of Unit 10 Oscillations and Waves which has a weightage of 10 marks in the Class 11 Physics Examination. The chapter covers concepts of transverse and longitudinal waves, the principle of superposition of waves, and the Doppler effect.

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NCERT Solutions for Class 11 Physics Chapter 15

The NCERT Solutions for Chapter 15 of Class 11 Physics are as given below –

Class 11 Physics Chapter 15 – Concepts Covered

A wave is a disturbance that travels through a material medium as a result of the repeated periodic motion of the particles of the medium about their mean positions without any actual transportation of matter.

The particles of the medium traversed by a wave have relatively small vibrations about their mean positions. However, the particles are not displaced permanently in the direction of propagation of the wave.

Mechanical waves can be propagated or produced only in a material medium.

These waves work on Newton’s laws of motion. For example, waves on strings, waves on the water surface, sound waves etc.

Electromagnetic Waves are waves that do not require any material medium for their production and propagation. They can pass through a vacuum or any other material medium.

Some examples of electromagnetic waves are visible light, ultraviolet light, microwaves, radio waves, etc.

Wave velocity is the time rate of propagation of wave motion in a given medium. It depends upon the nature of the medium.

Wave velocity (υ) = frequency (v) x wavelength (λ)

Matter waves are associated with moving particles of matter, like protons, electrons, neutrons etc.

Class 11 Physics Chapter 15 Related Guides:

Beats	Unit of Wavelength	Laplace Correction
Wave Speed	Gravity Waves	Types of Waves
Amplitude Formula	Intensity Formula	Gravity Waves

Class 11 Physics Study Guides:

NCERT Solutions for Class 11 Physics	Class 11 Physics Notes	Derivations in Physics
Relation between articles in Physics	Difference between in Physics	SI Units in Physics
Physics Study Notes	Physics Constants	Physics Formula

CBSE CLASS XII Related Questions

1.
Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.
View Solution
2.
Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.
View Solution
3.
Two parallel plate capacitors X and Y are connected in series to a 6 V battery. They have the same plate area and same plate separation but capacitor X has air between its plates, whereas capacitor Y contains a material of dielectric constant 4. Calculate the capacitances of X and Y, if the equivalent capacitance of the combination of X and Y is \( 4 \, \mu\text{F} \). Calculate the potential difference across the plates of X and Y.
View Solution
4.
Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.
- Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Both Assertion (A) and Reason (R) are false.
View Solution
5.
Four independent waves are expressed as \[ (i)\; y_1=A_1\sin\omega t, \] \[ (ii)\; y_2=A_2\sin 2\omega t, \] \[ (iii)\; y_3=A_3\cos\omega t, \] \[ (iv)\; y_4=A_4\sin\left(\omega t+\frac{\pi}{3}\right) \] The interference between two of these waves is possible in
- (i) and (iii) only
- (iii) and (iv) only
- (i), (iii) and (iv) only
- All of them
View Solution
6.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:
- 5 V
- 3.5 V
- 2.5 V
- Zero V
View Solution

View All

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NCERT Solutions for class 11 Physics Chapter 15: Waves

NCERT Solutions for Class 11 Physics Chapter 15

Class 11 Physics Chapter 15 – Concepts Covered

CBSE CLASS XII Related Questions

1.
Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.

2.
Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.

4.
Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

5.
Four independent waves are expressed as \[ (i)\; y_1=A_1\sin\omega t, \] \[ (ii)\; y_2=A_2\sin 2\omega t, \] \[ (iii)\; y_3=A_3\cos\omega t, \] \[ (iv)\; y_4=A_4\sin\left(\omega t+\frac{\pi}{3}\right) \] The interference between two of these waves is possible in

6.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

Similar Physics Concepts

Comments

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NCERT Solutions for class 11 Physics Chapter 15: Waves

NCERT Solutions for Class 11 Physics Chapter 15

Class 11 Physics Chapter 15 – Concepts Covered

CBSE CLASS XII Related Questions

1.Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.

2. Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.

4.Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

5.Four independent waves are expressed as \[ (i)\; y_1=A_1\sin\omega t, \] \[ (ii)\; y_2=A_2\sin 2\omega t, \] \[ (iii)\; y_3=A_3\cos\omega t, \] \[ (iv)\; y_4=A_4\sin\left(\omega t+\frac{\pi}{3}\right) \] The interference between two of these waves is possible in

6.A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.

2.
Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.

4.
Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

5.
Four independent waves are expressed as \[ (i)\; y_1=A_1\sin\omega t, \] \[ (ii)\; y_2=A_2\sin 2\omega t, \] \[ (iii)\; y_3=A_3\cos\omega t, \] \[ (iv)\; y_4=A_4\sin\left(\omega t+\frac{\pi}{3}\right) \] The interference between two of these waves is possible in

6.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be: