NCERT Solutions For Class 11 Physics Chapter 5: Laws of Motion

NCERT Solutions for Class 11 Physics Chapter 5 Laws of Motion are provided in the article below. The branch of physics where we study the motion of a body by considering the cause which is the force which generates the motion is called Dynamics. Newton’s three laws of motion make us understand how objects act when standing still, while moving or when forces behave upon them.

Class 11 Physics Chapter 5 Laws of Motion belongs to Unit 3 which has a weightage of 23 marks along with Unit 2 Kinematics and Unit 3. The Class 11 Physics Chapter 5 NCERT Solutions deals with the concepts of force and Laws of Motion, Non-contact force, Inertia and Mass.

Download PDF: NCERT Solutions for Class 11 Physics Chapter 5

NCERT Solutions for Class 11 Physics Chapter 5

NCERT Solutions

Class 11 Physics Chapter 5 – Concepts Covered

Newton’s First Law of Motion is referred to as the “Law of Inertia”. The law defines inertia, an inertial frame of reference, and force.

A body will remain at rest or continue to be in motion with a uniform velocity unless an external force is applied to it.

Newton’s Second Law of Motion: When an external force is applied to a body with constant mass, the force produces an acceleration. The acceleration that is produced is directly proportional to the force and then inversely proportional to the mass of the body.

$\overrightarrow {F} = K {dP \over dt} = Km \overrightarrow a$

Newton’s Third Law of Motion: To every action, there is an equal and opposite reaction force.

When body A exerts a force on some other body B, then B exerts an equal and opposite force on A.

Linear momentum of a body is the product of the mass and velocity of the body.

Linear Momentum = mass x velocity

Impulse is the product of force and the small-time interval for which the force acts.

$Impulse= \int Fdt$

Class 11 Physics Chapter 5 Related Guides –

Banking of Roads	Types of Friction	Rolling Friction
Sliding Friction	Pseudo Force	Tension Force
Kinetic Friction	Motion in Physics	Derivation of Centripetal Acceleration
Coefficient of Static Friction	Aristotle Fallacy	Static Friction
Impending Motion	Interaction of Forces	Difference between momentum and inertia

Class 11 Physics Study Guides:

NCERT Solutions for Class 11 Physics	Class 11 Physics Notes	Relation between articles in Physics
Difference between in Physics	Physics Study Notes	SI Units in Physics
Derivations in Physics	Physics Constants	Physics Formula

CBSE CLASS XII Related Questions

1.
A magnet held vertically, with its north pole down, is dropped along the axis of a closed solenoid placed vertically on a table. If the observer looks down from the top,

the induced current will flow in the anticlockwise direction.
the induced current will flow in the clockwise direction.
no induced current will flow in the solenoid.
the magnet will fall with a constant velocity.

View Solution

2.
In a region, the electric potential varies as $V = 10 - 50x$, where $V$ is in volts and $x$ is in meters. The electric field in the region is

$10\ \text{N/C}$ along $+x$
$10\ \text{N/C}$ along $-x$
$50\ \text{N/C}$ along $+x$
$50\ \text{N/C}$ along $-x$

View Solution

3.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

5 V
3.5 V
2.5 V
Zero V

View Solution

4.
An electron is revolving around a proton in a circular orbit of radius $r$. Using classical physics, prove that the ratio of value of the angular momentum and the value of magnetic moment of electron revolving in the orbit is a constant.

View Solution

5.
(I) The real image of an object placed between $f$ and $2f$ from a convex lens can be seen on a screen placed at the image location. If the screen is removed, is the image still there? Explain.
(II) Plane and convex mirrors produce virtual images of objects. Can they produce real images under some circumstances? Explain.

View Solution

6.
A wire of length $L$ is bent round into (i) a square coil having $N$ turns and (ii) a circular coil having $N$ turns. The coil in both cases is free to turn about a vertical axis coinciding with the plane of the coil, in a uniform, horizontal magnetic field and carry the same currents. Find the ratio of the maximum value of the torque acting on the square coil to that on the circular coil.

View Solution

NCERT Solutions For Class 11 Physics Chapter 5: Laws of Motion

NCERT Solutions for Class 11 Physics Chapter 5

Class 11 Physics Chapter 5 – Concepts Covered

CBSE CLASS XII Related Questions

1.
A magnet held vertically, with its north pole down, is dropped along the axis of a closed solenoid placed vertically on a table. If the observer looks down from the top,

2.
In a region, the electric potential varies as \(V = 10 - 50x\), where \(V\) is in volts and \(x\) is in meters. The electric field in the region is

3.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

4.
An electron is revolving around a proton in a circular orbit of radius $r$. Using classical physics, prove that the ratio of value of the angular momentum and the value of magnetic moment of electron revolving in the orbit is a constant.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

NCERT Solutions For Class 11 Physics Chapter 5: Laws of Motion

NCERT Solutions for Class 11 Physics Chapter 5

Class 11 Physics Chapter 5 – Concepts Covered

CBSE CLASS XII Related Questions

1.A magnet held vertically, with its north pole down, is dropped along the axis of a closed solenoid placed vertically on a table. If the observer looks down from the top,

2.In a region, the electric potential varies as \(V = 10 - 50x\), where \(V\) is in volts and \(x\) is in meters. The electric field in the region is

3.A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

4.An electron is revolving around a proton in a circular orbit of radius $r$. Using classical physics, prove that the ratio of value of the angular momentum and the value of magnetic moment of electron revolving in the orbit is a constant.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
A magnet held vertically, with its north pole down, is dropped along the axis of a closed solenoid placed vertically on a table. If the observer looks down from the top,

2.
In a region, the electric potential varies as \(V = 10 - 50x\), where \(V\) is in volts and \(x\) is in meters. The electric field in the region is

3.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

4.
An electron is revolving around a proton in a circular orbit of radius $r$. Using classical physics, prove that the ratio of value of the angular momentum and the value of magnetic moment of electron revolving in the orbit is a constant.