NCERT Solutions for Class 7 Mathematics Chapter 11: Perimeter and Area

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NCERT Solutions for Class 7 Mathematics Chapter 11 Perimeter and Area is provided in this article. Two-dimensional forms have two key properties: area and perimeter. The perimeter of a form is defined by the distance between its boundary and the area occupied by it. Some of the important topics in Perimeter and Area chapter includes:

Rectangle
Difference Between Area and Perimeter
Area of Square Using Diagonal
Perimeter and Area Formula
Perimeter of Triangle
Square Footage Formula

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 11 pdf

NCERT Solutions for Class 7 Mathematics Chapter 11

NCERT Solutions for Class 7 Mathematics Chapter 11 Perimeter and Area is given below.

NCERT Solutions for Class 7 Mathematics

Area: It is the two-dimensional space occupied within the boundaries of a geometrical figure.

Perimeter: It is the length of the boundary of a two-dimensional geometrical figure.

Example 1: Find the area of a square of side 5 cm.

Ans. We know that,

Area of square = a x a

Area = 5 x 5

Area of square = 25 sq.cm

Example 2: Find the perimeter of square of side 10 cm.

Ans. We know that,

Perimeter of square = 4a

Perimeter = 4 x 5

Perimeter = 20 sq.cm

NCERT Solutions for Class 7 Maths Chapter 11 Exercises

NCERT Solutions for Class 7 Maths Chapter 11 Area and Perimeter Exercises are given below.

Read More:

Square Formula	Area Formulas
Area of Shapes	Perimeter of Square Formula

Class 7 Maths Study Guides:

NCERT Solutions for Class 7 Maths	Number System	Geometry
Arithmetics	Basic Maths	Maths Formulas

CBSE X Related Questions

1.
D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.
View Solution
2.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.
View Solution
3.
In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals
- \(2.5\) cm
- \(10.5\) cm
- \(3.5\) cm
- \(\frac{14}{3}\) cm
View Solution
4.
The natural number 1 is :
- a prime number.
- a composite number.
- prime as well as composite.
- neither prime nor composite.
View Solution
5.
If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).
View Solution
6.
The HCF of 960 and 432 is :
- 48
- 54
- 72
- 36
View Solution

View All

Mathematics Preparation Guides

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NCERT Solutions For Class 7 Science Chapter 15 : Visualizing Solid Shapes

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NCERT Solutions for Class 7 Mathematics Chapter 11: Perimeter and Area

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 11 pdf

NCERT Solutions for Class 7 Mathematics Chapter 11

NCERT Solutions for Class 7 Mathematics

NCERT Solutions for Class 7 Maths Chapter 11 Exercises

CBSE X Related Questions

1.
D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.

2.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.

3.
In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals

4.
The natural number 1 is :

5.
If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).

6.
The HCF of 960 and 432 is :

Comments

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NCERT Solutions for Class 7 Mathematics Chapter 11: Perimeter and Area

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 11 pdf

NCERT Solutions for Class 7 Mathematics Chapter 11

NCERT Solutions for Class 7 Mathematics

NCERT Solutions for Class 7 Maths Chapter 11 Exercises

CBSE X Related Questions

1.D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.

2.A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.

3.In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals

4.The natural number 1 is :

5.If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).

6.The HCF of 960 and 432 is :

Comments

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1.
D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.

2.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.

3.
In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals

4.
The natural number 1 is :

5.
If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).

6.
The HCF of 960 and 432 is :