NCERT Solutions for Class 7 Mathematics Chapter 12: Algebraic Expressions

Content Curator

Algebraic Expressions are provided in the article below. Algebraic Expression, also known as Variable Expression is made up of various terms such as addition, subtraction, multiplication, division, etc. Thus, we can say that 7x + 5 is an example of an algebraic expression. Some of the important topics in the Algebraic Expressions chapter include:

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 12 pdf

NCERT Solutions for Class 7 Mathematics Chapter 12

NCERT Solutions for Class 7 Mathematics Chapter 12 Algebraic Expressions is given below

NCERT Solutions

NCERT Solutions for Class 7 Mathematics

Algebraic Expression: Algebraic Expression is the combination of constants and variables connected by mathematical operators such as addition, subtraction, multiplication and division. Eg: 5x + 3y = 2

Constants: Constants are terms whose value does not change.

Variables: Variables are terms whose value changes. These are represented in terms of alphabets.

Example 1: Add 5x + 2y + 4 = 0 and 2x + 8y + 2 = 0

Ans. Adding (5x + 2y + 4 = 0) and (2x + 8y + 2 = 0)

we get,

7x + 10y + 6 = 0

Example 2: Expand (6x +2)²

Ans. We know that,

(a + b)² = a² + b² + 2ab

(6x + 2)²= (6x)² + 2² + 2. 6x . 2

= 36x²+24x + 4

NCERT Solutions for Class 7 Maths Chapter 12 Exercises

NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Exercises are given below.

Read More:

Like and Unlike Terms	Multiplication of algebraic terms	Variables and Constants

Class 7 Maths Study Guides:

NCERT Solutions for Class 7 Maths	Number System	Geometry
Arithmetics	Basic Maths	Maths Formulas

CBSE X Related Questions

1.
The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are
- $(x + 2), (x - 5)$
- $(x + 5), (x - 2)$
- $(x + 1), (x - 5)$
- $(x - 1), (x + 2)$
View Solution
2.
If for a data, median is 5 and mode is 4, then mean is equal to :
- 7
- 11
- $\frac{11}{2}$
- $\frac{14}{3}$
View Solution
3.
If $ \alpha $ and $ \beta $ are two zeroes of a polynomial $ f(x) = px^2 - 2x + 3p $ and $ \alpha + \beta = \alpha\beta $, then value of p is :
- $ -\frac{2}{3} $
- $ \frac{2}{3} $
- $ \frac{1}{3} $
- $ -\frac{1}{3} $
View Solution
4.
In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is
- $6$
- $4$
- $\pm 4$
- $3$
View Solution
5.
In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is
- $55^\circ$
- $20^\circ$
- $35^\circ$
- $70^\circ$
View Solution
6.
If $PQ$ and $PR$ are tangents to the circle with centre $O$ and radius $4 \text{ cm}$ such that $\angle QPR = 90^{\circ}$, then the length $OP$ is
- $4 \text{ cm}$
- $4\sqrt{2} \text{ cm}$
- $8 \text{ cm}$
- $2\sqrt{2} \text{ cm}$
View Solution

View All

Mathematics Preparation Guides

Area of a Triangle: Formula, Types & Examples

Isosceles Triangle Theorems: Proof and Sample Questions

How to Calculate Percentage: Formula, Basic Tricks, Solved Examples

Difference Between Area and Perimeter: Definitions & Formulas

Area of Square Using Diagonal: Formula, Relation & Derivation

Additive Inverse: Formula, Properties, Fraction & Complex Numbers

BODMAS Rule: Definition, Rules and Sample Questions

Isosceles Right Triangle: Formulas, Pythagoras Theorem and Area

Unitary Method: Steps, Types of Unitary Method, Solved Examples

Triangle Theorems: Properties, Types & Similarity Theorems

Percentage: Formula, Conversions and Examples

Area of Isosceles Triangle: Formula, Properties & Examples

Area and Perimeter: Definition, Formulas & Examples

Commutative Property: Formula, Properties, Sample Questions

Perimeter of a Trapezoid Formula: Perimeter, Quadrilateral, Polygons

Interest Formula: Simple and Compound Interest, Differences

Percentage Formula: How to Calculate Percentage?

Difference Between In Maths: Comparison Articles

Percentage Change, Percent Decrease Formula, Sample Questions

Percentage Change Formula: Solved Examples

Mathematics NCERT Solutions

Difference Between Cube and Cuboid: Explanation and Examples

Triangle Inequality Theorem: Mechanism and Proof

NCERT Solutions for Class 7 Mathematics Chapter 1: Integers

NCERT Solutions for Class 7 Mathematics Chapter 10: Practical Geometry

NCERT Solutions for Class 7 Mathematics Chapter 14: Symmetry

NCERT Solutions for Class 7 Mathematics Chapter 5: Lines and Angles

NCERT Solutions for Class 7 Mathematics Chapter 9: Rational Numbers

NCERT Solutions For Class 7 Science Chapter 15 : Visualizing Solid Shapes

NCERT Solutions For Class 7 Mathematics Chapter 4: Simple Equations

NCERT Solutions for Class 7 Mathematics Chapter 8: Comparing Quantities

NCERT Solutions for Class 7 Mathematics Chapter 12: Algebraic Expressions

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 12 pdf

NCERT Solutions for Class 7 Mathematics Chapter 12

NCERT Solutions for Class 7 Mathematics

NCERT Solutions for Class 7 Maths Chapter 12 Exercises

CBSE X Related Questions

1.
The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

2.
If for a data, median is 5 and mode is 4, then mean is equal to :

3.
If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

4.
In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

5.
In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is

6.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

Comments

SUBSCRIBE TO OUR NEWS LETTER

NCERT Solutions for Class 7 Mathematics Chapter 12: Algebraic Expressions

​Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 12 pdf

NCERT Solutions for Class 7 Mathematics Chapter 12

NCERT Solutions for Class 7 Mathematics

NCERT Solutions for Class 7 Maths Chapter 12 Exercises

CBSE X Related Questions

1.The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

2.If for a data, median is 5 and mode is 4, then mean is equal to :

3.If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

4.In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

5.In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is

6.If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

Comments

SUBSCRIBE TO OUR NEWS LETTER

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 12 pdf

1.
The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

2.
If for a data, median is 5 and mode is 4, then mean is equal to :

3.
If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

4.
In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

5.
In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is

6.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is