NCERT Solutions for Class 7 Maths Chapter 7 Exercise 7.1

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NCERT Solutions for Class 7 Maths Chapter 7 Congruence of Triangles Exercise 7.1 is provided for student reference in the form of a pdf file below. Exercise 7.1 broadly discusses the congruence of plane figures, congruence among line segments, congruence of angles, and congruence of triangles

Two or more objects are congruent if they are exact copies of each other. The method of superposition examines the congruence of plane figures. Some of the important take away noted for this exercise are:

  • If two line segments have equal length, they are congruent. Also, if two line segments are congruent, they have the same length. 
  • If two angles have the same measure, they are congruent. Also, if two angles are congruent, their measures are the same.
  • Two triangles are congruent if they are copies of each other and when superposed, i.e. they cover each other exactly

Download PDF: NCERT Solutions for Class 7 Maths Chapter 7 Exercise 7.1

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Examples From Class 7 Chapter 7 Congruence of Triangles

Ques. In the figure, PQR is a triangle in which PQ = PR. The medians of the triangle are QM and RN. Prove: 

(a) ΔNQR = ΔMRQ

(b) QM = RN

(c) ΔPMQ = ΔPNR

In the figure, PQR is a triangle in which PQ = PR. The medians of the triangle are QM and RN.

Ans.

In the figure, 

ΔPQR is an isosceles triangle (PQ = PR)

Therefore, ½ of PQ = ½ of PR

Thus, NQ = MR and PN = PM

  1. Considering ΔNQR and ΔMRQ

NQ = MR (half of the equal sides are also equal)

Also, 

∠NQR = ∠MRQ (angles opposite to equal sides are also equal)

QR = RQ (common side)

Therefore, 

ΔNQR = ΔMRQ (by SAS criterion)

  1. We know that congruent parts of the congruent triangle are also equal. Hence, QM = RN
  2. In ΔPMQ and ΔPNR

PN = PM (half of the equal sides are also equal)

We know that 

PR = PQ 

∠P = ∠P (common angles)

Therefore,

ΔPMQ = ΔPNR (by SAS criterion)

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