NCERT Solutions for class 7 Mathematics Chapter 7: Congruence of Triangles

NCERT Solutions for class 7 Mathematics Chapter 7 Congruence of Triangles are provided in the article below. Two triangles are congruent if their corresponding sides are equal in length, and their corresponding angles are equal in measure. Some of the important topics in Congruence of Triangles chapter include:

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 7 pdf

NCERT Solutions for Class 7 Mathematics Chapter 7

NCERT Solutions for Class 7 Mathematics Chapter 7 Congruence of Triangles is given below.

Class 7 Maths Chapter 7 – Important Topics

Congruence of Triangles: Any two triangles are said to be congruent if all the 3 corresponding sides and angles of triangles are equal in measure. The conditions of congruency are given below.

SSS (Side-Side-Side) – Two triangles are said to be congruent by SSS condition if all three sides are equal.
SAS(Side-Angle-Side) – Two triangles are said to be congruent by SAS condition if their two sides and 1 angle are equal.
ASA(Angle-Side-Angle) – Two triangles are said to be congruent by ASA condition if their two angles and 1 side are equal.
AAS(Angle-Angle-Side) – Two triangles are said to be congruent by AAS condition if their two angles and 1 side are equal.
RHS (Right angle- Hypotenuse-Side) – If the hypotenuse and side of one right-angled triangle are equal to the hypotenuse and the corresponding side of another right-angled triangle, the two triangles are congruent.

Example: In triangle ABC, if AB=AC and ∠B= 70°, then what is the value of ∠A?

Ans.

In a Δ ABC

AB=AC (Given)

∠B=∠C= 70°, (Angle opposite to equal sides are equal)

As per angle sum property some of 3 angles of a triangle is 180 degrees.

∠A + ∠B +∠C= 180°

∠A+70°+70°= 180°

∠A = 180° – 140°

∠A=40°

NCERT Solutions for Class 7 Maths Chapter 7 Exercises

NCERT Solutions for Class 7 Maths Chapter 7 Congruence of Triangles Exercises are given below.

Read More:

Obtuse Angled Triangle	Circumcentre of a Triangle	Similar Figures
Right Angle Triangle Theorem	Altitude Mean Triangle	Triangle MCQ
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NCERT Solutions for Class 7 Maths	Number System	Geometry
Arithmetics	Basic Maths	Maths Formulas

CBSE X Related Questions

1.
Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$
View Solution
2.
In the given figure, $AB \parallel DE$ and $AC \parallel DF$. Show that $\Delta ABC \sim \Delta DEF$. If $BC = 10\text{ cm}$, $EB = CF = 5\text{ cm}$ and $AB = 7\text{ cm}$, then find the length $DE$.
View Solution
3.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.
View Solution
4.
A kite is flying at a height of $60 \text{ m}$ above the ground level. Ravi, standing at the roof of the house is holding the string straight and observes the angle of elevation of kite as $30^{\circ}$. From the bottom of the same building, the angle of elevation of kite is $45^{\circ}$. Find the length of the string and height of roof from the ground. (Use $\sqrt{3} = 1.73$)
View Solution
5.
If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals
- $x^2 + 5x - 4$
- $(x + 3) (-x + 8)$
- $a(x^2 + 5x - 24)$
- $x^2 - 24$
View Solution
6.
In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.
View Solution

View All

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NCERT Solutions for class 7 Mathematics Chapter 7: Congruence of Triangles

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 7 pdf

NCERT Solutions for Class 7 Mathematics Chapter 7

Class 7 Maths Chapter 7 – Important Topics

NCERT Solutions for Class 7 Maths Chapter 7 Exercises

CBSE X Related Questions

1.
Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$

2.
In the given figure, $AB \parallel DE$ and $AC \parallel DF$. Show that $\Delta ABC \sim \Delta DEF$. If $BC = 10\text{ cm}$, $EB = CF = 5\text{ cm}$ and $AB = 7\text{ cm}$, then find the length $DE$.

3.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

5.
If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

6.
In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.

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NCERT Solutions for class 7 Mathematics Chapter 7: Congruence of Triangles

​Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 7 pdf

NCERT Solutions for Class 7 Mathematics Chapter 7

Class 7 Maths Chapter 7 – Important Topics

NCERT Solutions for Class 7 Maths Chapter 7 Exercises

CBSE X Related Questions

1.Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$

2.In the given figure, $AB \parallel DE$ and $AC \parallel DF$. Show that $\Delta ABC \sim \Delta DEF$. If $BC = 10\text{ cm}$, $EB = CF = 5\text{ cm}$ and $AB = 7\text{ cm}$, then find the length $DE$.

3.Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

5.If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

6.In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.

Comments

SUBSCRIBE TO OUR NEWS LETTER

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 7 pdf

1.
Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$

2.
In the given figure, $AB \parallel DE$ and $AC \parallel DF$. Show that $\Delta ABC \sim \Delta DEF$. If $BC = 10\text{ cm}$, $EB = CF = 5\text{ cm}$ and $AB = 7\text{ cm}$, then find the length $DE$.

3.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

5.
If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

6.
In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.