NCERT Solutions for class 7 Mathematics Chapter 7: Congruence of Triangles

NCERT Solutions for class 7 Mathematics Chapter 7 Congruence of Triangles are provided in the article below. Two triangles are congruent if their corresponding sides are equal in length, and their corresponding angles are equal in measure. Some of the important topics in Congruence of Triangles chapter include:

  1. Similarity of Triangles
  2. Pythagoras Theorem
  3. Congruence of Triangles
  4. Area of Similar Figures
  5. Mid point Theorem
  6. Triangular Numbers

​Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 7 pdf


NCERT Solutions for Class 7 Mathematics Chapter 7

NCERT Solutions for Class 7 Mathematics Chapter 7 Congruence of Triangles is given below.

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Class 7 Maths Chapter 7 – Important Topics

Congruence of Triangles: Any two triangles are said to be congruent if all the 3 corresponding sides and angles of triangles are equal in measure. The conditions of congruency are given below.

  1. SSS (Side-Side-Side) – Two triangles are said to be congruent by SSS condition if all three sides are equal.
  2. SAS(Side-Angle-Side) – Two triangles are said to be congruent by SAS condition if their two sides and 1 angle are equal.
  3. ASA(Angle-Side-Angle) – Two triangles are said to be congruent by ASA condition if their two angles and 1 side are equal.
  4. AAS(Angle-Angle-Side) – Two triangles are said to be congruent by AAS condition if their two angles and 1 side are equal.
  5. RHS (Right angle- Hypotenuse-Side) – If the hypotenuse and side of one right-angled triangle are equal to the hypotenuse and the corresponding side of another right-angled triangle, the two triangles are congruent.

Example: In triangle ABC, if AB=AC and ∠B= 70°, then what is the value of ∠A?

Ans. 

In a Δ ABC

AB=AC (Given)

∠B=∠C= 70°, (Angle opposite to equal sides are equal)

As per angle sum property some of 3 angles of a triangle is 180 degrees. 

∠A + ∠B +∠C= 180°

∠A+70°+70°= 180°

∠A = 180° – 140°

∠A=40°


NCERT Solutions for Class 7 Maths Chapter 7 Exercises

NCERT Solutions for Class 7 Maths Chapter 7 Congruence of Triangles Exercises are given below.

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Class 7 Study Guides:

CBSE X Related Questions

  • 1.
    The HCF of 960 and 432 is :

      • 48
      • 54
      • 72
      • 36

    • 2.
      If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

        • \(4 \text{ cm}\)
        • \(4\sqrt{2} \text{ cm}\)
        • \(8 \text{ cm}\)
        • \(2\sqrt{2} \text{ cm}\)

      • 3.
        If the quadratic equation \(9x^2 + 8kx + 16 = 0\) has real and equal roots, then the value of k is

          • 3
          • –3
          • –4
          • \(\pm 3\)

        • 4.
          A circle centered at (2, 1) passes through the points A(5, 6) and B(-3, K). Find the value(s) of K. Hence find length of chord AB.


            • 5.
              The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

                • 0
                • 1
                • 3
                • 2

              • 6.
                D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.

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