NCERT Solutions for Class 9 Maths Chapter 1 Exercise 1.1 Solutions

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NCERT Solutions for Class 9 Maths Chapter 1 Number Systems Exercise 1.1 Solutions are based on finding rational numbers between two given numbers.

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Check out NCERT Solutions for Class 9 Maths Chapter 1 Exercise 1.1 Solutions

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Exercise Solutions of Class 9 Maths Chapter 1 Number Systems

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Chapter Related Topics
Rationalize the denominator	Irrational Numbers	Addition And Subtraction Of Integers?
Relation between hcf and lcm?	Decimal expansion of rational numbers?	Integers As Exponents?
Multiplication And Division Of Integers?	Operations on Rational Numbers?	Number System

Also check:

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Trigonometry	Number Systems	Mensuration
Math Formula	NCERT Solutions for Class 9 Maths	Geometry

CBSE X Related Questions

1.
If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).
View Solution
2.
There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?
- 144
- 2
- 420
- 272
View Solution
3.
The natural number 1 is :
- a prime number.
- a composite number.
- prime as well as composite.
- neither prime nor composite.
View Solution
4.
In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals
- \(2.5\) cm
- \(10.5\) cm
- \(3.5\) cm
- \(\frac{14}{3}\) cm
View Solution
5.
The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :
- 0
- 1
- 3
- 2
View Solution
6.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is
- \(4 \text{ cm}\)
- \(4\sqrt{2} \text{ cm}\)
- \(8 \text{ cm}\)
- \(2\sqrt{2} \text{ cm}\)
View Solution

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