NCERT Solutions for Class 9 Maths Chapter 1 Exercise 1.4 Solutions

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NCERT Solutions for Class 9 Maths Chapter 1 Number Systems Exercise 1.4 Solutions are based on the representation of real numbers on the number line.

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Check out NCERT Solutions for Class 9 Maths Chapter 1 Exercise 1.4 Solutions

Read More: NCERT Solutions For Class 9 Maths Chapter 1 Number Systems

Exercise Solutions of Class 9 Maths Chapter 1 Number Systems

Also check other Exercise Solutions of Class 9 Maths Chapter 1 Number Systems

Also Check:

Chapter Related Topics
Rationalize the denominator	Irrational Numbers	Addition And Subtraction Of Integers?
Relation between hcf and lcm?	Decimal expansion of rational numbers?	Integers As Exponents?
Multiplication And Division Of Integers?	Operations on Rational Numbers?	Number System

Also check:

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Difference Between Topics in Maths	Math Study Material	Algebra
Trigonometry	Number Systems	Mensuration
Math Formula	NCERT Solutions for Class 9 Maths	Geometry

CBSE X Related Questions

1.
The HCF of 960 and 432 is :
- 48
- 54
- 72
- 36
View Solution
2.
Two water taps together can fill a tank in $8\frac{8}{9}$ hours. The tap of larger diameter takes 4 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.
View Solution
3.
If the quadratic equation \(9x^2 + 8kx + 16 = 0\) has real and equal roots, then the value of k is
- 3
- –3
- –4
- \(\pm 3\)
View Solution
4.
A kite is flying at a height of \(60 \text{ m}\) above the ground level. Ravi, standing at the roof of the house is holding the string straight and observes the angle of elevation of kite as \(30^{\circ}\). From the bottom of the same building, the angle of elevation of kite is \(45^{\circ}\). Find the length of the string and height of roof from the ground. (Use \(\sqrt{3} = 1.73\))
View Solution
5.
PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.
View Solution
6.
The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :
- $q - 9p$
- $p - 9q$
- $p + 9q$
- $2p + 9q$
View Solution

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