NCERT Solutions for Class 9 Maths Chapter 1 Exercise 1.4 Solutions

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NCERT Solutions for Class 9 Maths Chapter 1 Number Systems Exercise 1.4 Solutions are based on the representation of real numbers on the number line.

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Check out NCERT Solutions for Class 9 Maths Chapter 1 Exercise 1.4 Solutions

Read More: NCERT Solutions For Class 9 Maths Chapter 1 Number Systems

Exercise Solutions of Class 9 Maths Chapter 1 Number Systems

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Chapter Related Topics
Rationalize the denominator	Irrational Numbers	Addition And Subtraction Of Integers?
Relation between hcf and lcm?	Decimal expansion of rational numbers?	Integers As Exponents?
Multiplication And Division Of Integers?	Operations on Rational Numbers?	Number System

Also check:

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Difference Between Topics in Maths	Math Study Material	Algebra
Trigonometry	Number Systems	Mensuration
Math Formula	NCERT Solutions for Class 9 Maths	Geometry

CBSE X Related Questions

1.
The natural number 1 is :
- a prime number.
- a composite number.
- prime as well as composite.
- neither prime nor composite.
View Solution
2.
PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.
View Solution
3.
The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :
- 0
- 1
- 3
- 2
View Solution
4.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is
- \(4 \text{ cm}\)
- \(4\sqrt{2} \text{ cm}\)
- \(8 \text{ cm}\)
- \(2\sqrt{2} \text{ cm}\)
View Solution
5.
D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.
View Solution
6.
Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)
View Solution

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