NCERT Solutions for Class 9 Maths Chapter 1 Exercise 1.5 Solutions

CBSE X Related Questions

  • 1.
    \(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

      • \(\frac{21}{4} \text{ cm}\)
      • \(\frac{28}{3} \text{ cm}\)
      • \(\frac{12}{7} \text{ cm}\)
      • \(5.5 \text{ cm}\)

    • 2.
      If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

        • $x^2 + 5x - 4$
        • $(x + 3) (-x + 8)$
        • $a(x^2 + 5x - 24)$
        • $x^2 - 24$

      • 3.
        Prove that :
        \(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).


          • 4.
            A kite is flying at a height of \(60 \text{ m}\) above the ground level. Ravi, standing at the roof of the house is holding the string straight and observes the angle of elevation of kite as \(30^{\circ}\). From the bottom of the same building, the angle of elevation of kite is \(45^{\circ}\). Find the length of the string and height of roof from the ground. (Use \(\sqrt{3} = 1.73\))


              • 5.
                In the figure given above, \(\triangle ABC \sim \triangle XYZ\), then find the values of \(x\) and \(y\).


                  • 6.
                    PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.

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