NCERT Solutions for Class 9 Maths Chapter 1 Exercise 1.4 Solutions

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CBSE X Related Questions

  • 1.
    Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

      • 34
      • 43
      • 38.5
      • 41.5

    • 2.
      The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

        • \((x + 2), (x - 5)\)
        • \((x + 5), (x - 2)\)
        • \((x + 1), (x - 5)\)
        • \((x - 1), (x + 2)\)

      • 3.
        Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

          • \(10^{\circ}\)
          • \(60^{\circ}\)
          • \(45^{\circ}\)
          • \(100^{\circ}\)

        • 4.
          The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is

            • 2
            • \(-6\)
            • \(-2\)
            • 6

          • 5.
            If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

              • \(4 \text{ cm}\)
              • \(4\sqrt{2} \text{ cm}\)
              • \(8 \text{ cm}\)
              • \(2\sqrt{2} \text{ cm}\)

            • 6.
              If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

                • \( -\frac{2}{3} \)
                • \( \frac{2}{3} \)
                • \( \frac{1}{3} \)
                • \( -\frac{1}{3} \)

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