NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13 1 Solutions

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NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13.1 Solutions are based on the concept of Surface area of a cuboid and a cube.

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Read More: NCERT Solutions For Class 9 Maths Chapter 13 Surface Areas and Volumes

Exercise Solutions of Class 9 Maths Chapter 13 Surface Areas and Volumes

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CBSE X Related Questions

  • 1.
    If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

      • $x^2 + 5x - 4$
      • $(x + 3) (-x + 8)$
      • $a(x^2 + 5x - 24)$
      • $x^2 - 24$

    • 2.
      A kite is flying at a height of \(60 \text{ m}\) above the ground level. Ravi, standing at the roof of the house is holding the string straight and observes the angle of elevation of kite as \(30^{\circ}\). From the bottom of the same building, the angle of elevation of kite is \(45^{\circ}\). Find the length of the string and height of roof from the ground. (Use \(\sqrt{3} = 1.73\))


        • 3.
          Two water taps together can fill a tank in $8\frac{8}{9}$ hours. The tap of larger diameter takes 4 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.


            • 4.
              In the figure given above, \(\triangle ABC \sim \triangle XYZ\), then find the values of \(x\) and \(y\).


                • 5.
                  The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :

                    • $q - 9p$
                    • $p - 9q$
                    • $p + 9q$
                    • $2p + 9q$

                  • 6.
                    If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then

                      • \( \frac{a_1}{a_2} \neq \frac{b_1}{b_2} \)
                      • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
                      • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} \)
                      • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)

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