NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13.8 Solutions

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NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13.8 Solutions are based on the volume of a sphere.

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Read More: NCERT Solutions For Class 9 Maths Chapter 13 Surface Areas and Volumes

Exercise Solutions of Class 9 Maths Chapter 13 Surface Areas and Volumes

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CBSE X Related Questions

  • 1.
    If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

      • \( -\frac{2}{3} \)
      • \( \frac{2}{3} \)
      • \( \frac{1}{3} \)
      • \( -\frac{1}{3} \)

    • 2.
      There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

        • 144
        • 2
        • 420
        • 272

      • 3.
        If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

          • \(\frac{7}{2}\)
          • \(\frac{6}{7}\)
          • \(\frac{-7}{6}\)
          • \(\frac{7}{6}\)

        • 4.
          If roots of the quadratic equation \(x^2 - k\sqrt{3}x + 2 = 0\) are real and equal, then value of k is

            • \(-2\)
            • \(\sqrt{\frac{8}{3}}\)
            • \(1\)
            • \(2\)

          • 5.
            If for a data, median is 5 and mode is 4, then mean is equal to :

              • 7
              • 11
              • \(\frac{11}{2}\)
              • \(\frac{14}{3}\)

            • 6.
              It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

                • \(\frac{\text{Perimeter of } \triangle ABC}{\text{Perimeter of } \triangle EDF} = \frac{AB}{ED}\)
                • \(\frac{AB}{ED} = \frac{AC}{EF}\)
                • \(\angle A = \angle D, \angle C = \angle F\)
                • \(\frac{AB + BC}{AC} = \frac{ED + DF}{EF}\)

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