NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13.4 Solutions

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NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13.4 Solutions are based on the concept of Surface area of a sphere.

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Read More: NCERT Solutions For Class 9 Maths Chapter 13 Surface Areas and Volumes

Exercise Solutions of Class 9 Maths Chapter 13 Surface Areas and Volumes

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CBSE X Related Questions

  • 1.
    Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

      • \(10^{\circ}\)
      • \(60^{\circ}\)
      • \(45^{\circ}\)
      • \(100^{\circ}\)

    • 2.
      If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

        • \( -\frac{2}{3} \)
        • \( \frac{2}{3} \)
        • \( \frac{1}{3} \)
        • \( -\frac{1}{3} \)

      • 3.
        In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

          • $6$
          • $4$
          • $\pm 4$
          • $3$

        • 4.
          It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

            • \(\frac{\text{Perimeter of } \triangle ABC}{\text{Perimeter of } \triangle EDF} = \frac{AB}{ED}\)
            • \(\frac{AB}{ED} = \frac{AC}{EF}\)
            • \(\angle A = \angle D, \angle C = \angle F\)
            • \(\frac{AB + BC}{AC} = \frac{ED + DF}{EF}\)

          • 5.
            If for a data, median is 5 and mode is 4, then mean is equal to :

              • 7
              • 11
              • \(\frac{11}{2}\)
              • \(\frac{14}{3}\)

            • 6.
              The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

                • \((x + 2), (x - 5)\)
                • \((x + 5), (x - 2)\)
                • \((x + 1), (x - 5)\)
                • \((x - 1), (x + 2)\)

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