NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13.7 Solutions

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NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13.7 Solutions are based on the volume of a right circular cone.

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Read More: NCERT Solutions For Class 9 Maths Chapter 13 Surface Areas and Volumes

Exercise Solutions of Class 9 Maths Chapter 13 Surface Areas and Volumes

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CBSE X Related Questions

  • 1.
    Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

      • \(10^{\circ}\)
      • \(60^{\circ}\)
      • \(45^{\circ}\)
      • \(100^{\circ}\)

    • 2.
      If roots of the quadratic equation \(x^2 - k\sqrt{3}x + 2 = 0\) are real and equal, then value of k is

        • \(-2\)
        • \(\sqrt{\frac{8}{3}}\)
        • \(1\)
        • \(2\)

      • 3.
        If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

          • \(\frac{7}{2}\)
          • \(\frac{6}{7}\)
          • \(\frac{-7}{6}\)
          • \(\frac{7}{6}\)

        • 4.
          Which of the following graphs represents a polynomial with both zeroes being positive?


          • 5.
            The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is

              • 2
              • \(-6\)
              • \(-2\)
              • 6

            • 6.
              The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

                • \((x + 2), (x - 5)\)
                • \((x + 5), (x - 2)\)
                • \((x + 1), (x - 5)\)
                • \((x - 1), (x + 2)\)

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