NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13.5 Solutions

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NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13.5 Solutions are based on the Volume of a cuboid.

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Read More: NCERT Solutions For Class 9 Maths Chapter 13 Surface Areas and Volumes

Exercise Solutions of Class 9 Maths Chapter 13 Surface Areas and Volumes

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CBSE X Related Questions

  • 1.
    If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

      • $x^2 + 5x - 4$
      • $(x + 3) (-x + 8)$
      • $a(x^2 + 5x - 24)$
      • $x^2 - 24$

    • 2.
      If the quadratic equation \(9x^2 + 8kx + 16 = 0\) has real and equal roots, then the value of k is

        • 3
        • –3
        • –4
        • \(\pm 3\)

      • 3.
        \(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

          • \(\frac{21}{4} \text{ cm}\)
          • \(\frac{28}{3} \text{ cm}\)
          • \(\frac{12}{7} \text{ cm}\)
          • \(5.5 \text{ cm}\)

        • 4.
          In the figure given above, \(\triangle ABC \sim \triangle XYZ\), then find the values of \(x\) and \(y\).


            • 5.
              The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :

                • $q - 9p$
                • $p - 9q$
                • $p + 9q$
                • $2p + 9q$

              • 6.
                If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then

                  • \( \frac{a_1}{a_2} \neq \frac{b_1}{b_2} \)
                  • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
                  • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} \)
                  • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)

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