NCERT Solutions for Class 10 Maths Chapter 9: Some Applications of Trigonometry

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The NCERT Solutions for Class 10 Maths Chapter 9 Some Applications of Trigonometry are provided in this article. The chapter discusses how trigonometry is helpful in finding the height and distance of various objects without measuring them directly. Trigonometry is mostly used in geography and navigation to locate the position of a place in relation to latitude and longitude.

Class 10 Maths Chapter 9 Some Applications of Trigonometry belongs to Unit 5 Trigonometry which has a weightage of 12 marks in the CBSE Class 10 Maths Examination. The questions from this chapter are based on heights and distances and angles of depression.

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NCERT Solutions for Class 10 Maths Chapter 9

Important Topics in Class 10 Maths Chapter 9

Line of sight and horizontal level

Line of sight is the line from the eye of the observer to the point of the object viewed by the observer. Horizontal level is a horizontal line through the eye of the observer.

The angle of elevation is the angle formed by the line of sight with the horizontal level.

Angle of elevation is relevant for objects that are above horizontal level.

The angle of depression is the angle that is formed between the line of sight and the horizontal level.

Angle of depression is is relevant for objects that are below horizontal level.

Calculating Heights and Distances: To calculate the heights and distances, we make use of trigonometric ratios.

Step 1: Draw a line diagram that corresponds to the given problem.

Step 2: Mark all the known angles, heights, and distances. Denote the unknown lengths by variables such as x,y, etc.

Step 3: Use the values of different trigonometric ratios of the angles to find the unknown lengths from the given lengths.

Some Applications of Trigonometry – Related Topics:

Some Applications of Trigonometry Revision Notes	Some applications of trigonometry Important Questions	Trigonometric Identities
Trigonometry Table	Trigonometry Ratios	Trigonometry Values

CBSE Class 10 Mathematics Study Guides:

NCERT Solutions for Class 10 Maths	Class 10 Maths Notes	Maths Study Material
Geometry	Math MCQs	Difference between in Maths
Mensuration	Calculus	Math Formula

CBSE X Related Questions

1.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.
View Solution
2.
A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.
View Solution
3.
Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.
View Solution
4.
The natural number 1 is :
- a prime number.
- a composite number.
- prime as well as composite.
- neither prime nor composite.
View Solution
5.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.
View Solution
6.
The dimensions of a window are $156\text{ cm} \times 216\text{ cm}$. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.
View Solution

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NCERT Solutions for Class 10 Maths Chapter 9: Some Applications of Trigonometry

NCERT Solutions for Class 10 Maths Chapter 9

Important Topics in Class 10 Maths Chapter 9

CBSE X Related Questions

1.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

2.
A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.

3.
Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.

4.
The natural number 1 is :

5.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.

6.
The dimensions of a window are $156\text{ cm} \times 216\text{ cm}$. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.

Similar Mathematics Concepts

Comments

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NCERT Solutions for Class 10 Maths Chapter 9: Some Applications of Trigonometry

NCERT Solutions for Class 10 Maths Chapter 9

Important Topics in Class 10 Maths Chapter 9

CBSE X Related Questions

1.Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

2.A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.

3.Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.

4.The natural number 1 is :

5.A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.

6.The dimensions of a window are $156\text{ cm} \times 216\text{ cm}$. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

2.
A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.

3.
Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.

4.
The natural number 1 is :

5.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.

6.
The dimensions of a window are $156\text{ cm} \times 216\text{ cm}$. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.