NCERT Solutions for Class 11 Maths Chapter 9 Exercise 9.3

Collegedunia Team logo

Collegedunia Team

Content Curator

Class 11 Maths NCERT Solutions Chapter 9 Sequence and Series Exercise 9.3 is based on the following concepts:

  • Relationship Between A.M. and G.M.

Download PDF NCERT Solutions for Class 11 Maths Chapter 9 Sequence and Series Exercise 9.3

Check out the solutions of Class 11 Maths NCERT solutions Chapter 9 Sequence and Series Exercise 9.3 

Read More: NCERT Solutions For Class 11 Maths Chapter 9 Sequence and Series

Also check other Exercise Solutions of Class 11 Maths Chapter 9 Sequence and Series

Also check:

Also check:

CBSE CLASS XII Related Questions

  • 1.

    Solve the differential equation \( y + \frac{d}{dx}(xy) = x(\sin x + \log x) \).


      • 2.

        Solve the differential equation \( (x+y)\,dy + (x-y)\,dx = 0 \), given that \( y(1) = 1 \).


          • 3.

            Find the sum of maximum and minimum values of \(f(x) = \sin x\,(1 + \cos x)\) in the interval \([0, \pi]\).


              • 4.

                The motion of a particle is described as \( S = 2t^{3} - 6t^{2} + 8 \). Its velocity \( \frac{dS}{dt} \), when the acceleration \( \frac{d^{2}S}{dt^{2}} \) vanishes is :

                  • \( -6 \) unit/sec
                  • \( 0 \) unit/sec
                  • \( 18 \) unit/sec
                  • \( 6 \) unit/sec

                • 5.

                  Find the product of the maximum and minimum values of the function \( f(x) = \cos x - \frac{1}{2}\cos 2x,\ x \in \left[0, \frac{\pi}{2}\right] \).


                    • 6.

                      If \(y = \sqrt{\log \left\{ \sin \left( \dfrac{x^2}{3} + 1 \right) \right\}}\), then show that

                      \[ \frac{dy}{dx} = \frac{x \cot \left( \dfrac{x^2}{3} + 1 \right)}{3y}. \]

                        CBSE CLASS XII Previous Year Papers

                        Comments


                        No Comments To Show