NCERT Solutions for Class 11 Maths Chapter 9 Miscellaneous Exercises

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Class 11 Maths NCERT Solutions Chapter 9 Sequence and Series Miscellaneous Exercises is based on the following concepts:

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CBSE CLASS XII Related Questions

  • 1.

    For two vectors \(\vec{a}\) and \(\vec{b}\):  

    Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]

      • Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).
      • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
      • Assertion (A) is true, but Reason (R) is false.
      • Assertion (A) is false, but Reason (R) is true.

    • 2.
      For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]

        • local maximum value is 2
        • local minimum value is \( -2 \)
        • local maximum value is \( -2 \)
        • local minimum value \( < \) local maximum value

      • 3.
        For a square matrix \(A\), \[ (3A)^{-1}= \]

          • \( 3A^{-1} \)
          • \( 9A^{-1} \)
          • \( \frac{1}{3} A^{-1} \)
          • \( \frac{1}{9} A^{-1} \)

        • 4.

          Check whether \[ f:\mathbb{R}-\{3\}\rightarrow\mathbb{R} \] defined as \[ f(x)=\frac{x-2}{x-3} \] is onto or not. 


            • 5.

              Sports car racing is a form of motorsport which uses sports car prototypes.The competition is held on special tracks designed in various shapes. 

              The equation of a sports car racing track is given as: \[ f(x)= \begin{cases} x^4-4x^2+4, & 0\leq x<3,\\ x^2+40, & x\geq 3 \end{cases} \] Based on this information:


                • 6.
                  Assertion (A) : In an experiment of throwing an unbiased die, the probability of getting a prime number given that number appearing on the die being odd is \( \frac{2}{3} \).
                  Reason (R) : For any two events \( A \) and \( B \), \( P(A|B) = \frac{P(A \cup B)}{P(B)} \).

                    • Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).
                    • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
                    • Assertion (A) is true and Reason (R) is false.
                    • Assertion (A) is false and Reason (R) is true.
                  CBSE CLASS XII Previous Year Papers

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