NCERT Solutions For Class 11 Physics Chapter 10: Mechanical Properties of Fluids

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NCERT Solutions for Class 11 Physics Chapter 10 Mechanical Properties of Fluids are given in this article. Fluids are substances that can flow e.g., liquids and gases. It does not possess definite shape. When an object is submerged in a liquid at rest, the fluid exerts a force on its surface normally.

Class 11 Physics Chapter 10 Mechanical Properties of Fluids belongs to Unit 7 Properties of Bulk Matter which has a weightage of 20 marks in the Class 11 Examination along with Unit 8 and Unit 9. NCERT Solutions for Mechanical Properties of Fluids covers concepts of Pascal’s law, Archimedes Principle, and Viscosity.

Download PDF: NCERT Solutions for Class 11 Physics Chapter 10

NCERT Solutions for Class 11 Physics Chapter 10

Class 11 Physics Chapter 10 – Concepts Covered

Pressure is the thrust experienced per unit area of the surface of a liquid that is at rest.

The pressure at any point in the liquid depends on the depth (h) below the surface, density of liquid and acceleration due to gravity.

Pascal’s Law states that the pressure applied to an enclosed liquid is transmitted to every portion of the liquid and walls of the containing vessel.

\(P = {F \over A}\)

Archimedes Principle: When a body is either partially or fully immersed in a liquid, it loses some of its weight. The loss in the weight of the body is equal to the weight of the liquid that is displaced by the immersed part.

The upward force that’s exerted by the liquid displaced when a body is immersed is known as buoyancy.

The energy possessed by a liquid by the virtue of its pressure is known as pressure energy.

Pressure energy of liquid in volume dV = PdV

Bernoulli’s Theorem: For an incompressible, irrotational, and non-viscous liquid with a streamlined flow, the sum of the kinetic energy, pressure energy, and potential energy per unit mass is a constant

\({P \over \rho} + {v^2 \over 2}+gh=constant\)

Class 11 Physics Chapter 10 Related Guides –

Hydraulic Machines	Bernoulli’s Principle	Venturimeter
Stokes’ Law	Surface Tension	Surface Energy
Barometer	Reynolds Number	Density
Buoyant Force	Fluid Friction	Fluid Pressure
Hydrostatic Paradox	Terminal Velocity Formula	Dynamic Lift

Class 11 Physics Study Guides:

NCERT Solutions for Class 11 Physics	Difference between in Physics	Relation between articles in Physics
Physics Formula	Physics Study Notes	SI Units in Physics
Derivations in Physics	Physics Constants	Class 11 Physics Notes

CBSE CLASS XII Related Questions

1.
A long solenoid of length \( L \) and radius \( r_1 \) having \( N_1 \) turns is surrounded symmetrically by a coil of radius \( r_2 \, (r_2>r_1) \) having \( N_2 \) turns (\( N_2 \ll N_1 \)) around its mid-point. Derive an expression for the mutual inductance of solenoid and coil. Is \( M_{12} = M_{21} \) valid in this case?
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2.
If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.
View Solution
3.
If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.
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4.
Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:
- attract with a force \( \frac{F}{2} \)
- repel with a force \( \frac{F}{2} \)
- repel with a force \( F \)
- attract with a force \( F \)
View Solution
5.
The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:
- \( \frac{q}{4 \pi \epsilon_0 l^2} \) pointing along MA
- \( \frac{q}{\pi \epsilon_0 l^2} \) pointing along AM
- \( \frac{q}{2 \pi \epsilon_0 l^2} \) pointing along AM
- Zero
View Solution
6.
Two parallel plate capacitors X and Y are connected in series to a 6 V battery. They have the same plate area and same plate separation but capacitor X has air between its plates, whereas capacitor Y contains a material of dielectric constant 4. Calculate the capacitances of X and Y, if the equivalent capacitance of the combination of X and Y is \( 4 \, \mu\text{F} \). Calculate the potential difference across the plates of X and Y.
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NCERT Solutions For Class 11 Physics Chapter 10: Mechanical Properties of Fluids

NCERT Solutions for Class 11 Physics Chapter 10

Class 11 Physics Chapter 10 – Concepts Covered

CBSE CLASS XII Related Questions

2.
If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

3.
If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.

4.
Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

5.
The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

Similar Physics Concepts

Comments

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NCERT Solutions For Class 11 Physics Chapter 10: Mechanical Properties of Fluids

NCERT Solutions for Class 11 Physics Chapter 10

Class 11 Physics Chapter 10 – Concepts Covered

CBSE CLASS XII Related Questions

2. If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

3. If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.

4.Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

5.The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

2.
If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

3.
If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.

4.
Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

5.
The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be: