NCERT Solutions for Class 9 Maths Chapter 2 Polynomials Exercise 2.2 Solutions

CBSE X Related Questions

  • 1.
    If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

      • \(4 \text{ cm}\)
      • \(4\sqrt{2} \text{ cm}\)
      • \(8 \text{ cm}\)
      • \(2\sqrt{2} \text{ cm}\)

    • 2.
      In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is

        • $55^\circ$
        • $20^\circ$
        • $35^\circ$
        • $70^\circ$

      • 3.
        If roots of the quadratic equation \(x^2 - k\sqrt{3}x + 2 = 0\) are real and equal, then value of k is

          • \(-2\)
          • \(\sqrt{\frac{8}{3}}\)
          • \(1\)
          • \(2\)

        • 4.
          There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

            • 144
            • 2
            • 420
            • 272

          • 5.
            If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

              • \( -\frac{2}{3} \)
              • \( \frac{2}{3} \)
              • \( \frac{1}{3} \)
              • \( -\frac{1}{3} \)

            • 6.
              For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

                • \(0\)
                • \(\frac{80}{81}\)
                • \(1\)
                • \(\frac{82}{80}\)

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