Synthetic Division: Concept, Polynomials, Steps & Examples

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Arpita Srivastava

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Synthetic Division is one of the ways to perform Euclidean division of polynomials. Polynomials can be divided by two methods, viz: long division method and synthetic division method. 

  • Synthetic division method is a shorter form of dividing the polynomials.
  • The long division method is a longer form of dividing the polynomials.
  • A polynomial is an expression made of variables, constants and exponents.
  • It requires fewer calculations and less time to solve the problem. 
  • It helps in finding zeros or the root of the polynomial.
  • The synthetic division method is the shorter form of dividing polynomials when dividing by a linear factor.
  • It is used to fix algorithms in CD players and telephones.
  • It involves adding the required polynomial expression.

Read More Polynomials Formulas

Key Terms: Synthetic Division, Euclidean division, Polynomials, Long division method, Linear factor, Whole number, Coefficient, Degree


Synthetic Division of Polynomials 

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Synthetic division method is a method that involves divison of polynomials with another polynomial equation with degree one. The method is used to count the number of zeroes of polynomials. 

  • It involves division of polynomial p(x) by a linear factor (x - a), which is a polynomial of degree 1.
  • Q(x) is the required quotient polynomial with a remainder R.
  • Mathematically, Synthetic division method can be represented as:

p(x)/q(x) = p(x)/(x- a) = Quotient + (Remainder/(x - a))

p(x)/(x - a) = Q(x) + (R/(x - a))

Read More: Quadrant


What are Polynomials

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Polynomial is a type of expression in mathematics in which exponents of all variables are a whole number. The degree of the polynomial is calculated by determining the highest value of the exponent.

  • It involves various operations like addition, subtraction, multiplication and division.
  • The power of any variable has to be a non-negative integer.

Solved Example

  • For example: 3x2 +2x +3 is a polynomial where x is known as a variable.
  • In this, 3 which is multiplied to x2 is coefficient, 3 is the constant, power of variable x is 2.

Polynomials

Polynomials  

Read More: Rationalize the Denominator

The video below explains this:

Polynomials Detailed Video Explanation:

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What is the Division of Polynomials?

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Division in Polynomials is an arithmetic operation, where a higher degree polynomial is divided by a lower degree or equivalent degree polynomial. It may result as a polynomial or as a constant in answer. It is usually done to find out the roots or zeros of the Polynomials

Polynomial Division

Polynomial Division

Read More: Nature of Roots


What Is Linear Factor?

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Linear Factor of a polynomial is a first degree polynomial which is the building block of higher degree polynomials. It appear in the form of ax+b. A linear factor of a polynomial is univariate meaning having one variable affecting the function.

Read More: Polynomials Formula


How To Perform Synthetic Division

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Synthetic Division method is a shorter form of dividing polynomials. It is generally used to find out zeros or roots of the polynomials. This division method is performed with less effort.

  • For synthetic Division method, the divisor of the polynomial should be degree 1 meaning it should be a linear factor.
  • The coefficient of the divisor variable should also be equal to 1.
  • Divide using the remainder theorem in conjunction with synthetic division.
  • Set up the coefficient and then divide.

Read More: Eccentricity


Steps of Synthetic Division

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The steps included in solving the synthetic division of polynomials are as follows:

Step 1

The setup is usually done as we divide in non-algebraic form. The divisor goes outside the box(divisor means the polynomial with which we are dividing) and the dividend goes inside the box.

  • Dividends are always written in descending order and insert zeros for the missing terms.
  • For example: (2x2 – 3x – 1) divided by (x+1) starts with degree four and degree three and degree two is missing so we put zeros on that place.
  • The said equation will be written as:
  • Setting this said equation up as a synthetic equation:

Steps Of Synthetic Division


 

Step 2

Bring down the first coefficient of the dividend.

Step 3

Multiply the coefficient of divisor with the brought down first coefficient of dividend then put the value just below the next coefficient.

Step 4

Add the column created.

Step 5

Repeat the steps that are multiplying the divisors coefficient with the previous dividends coefficient then add the same with the next coefficient.

Step 6

The numbers in the last row are coefficients of the quotient as well as the remainder. The final value on the right is the remainder.

  • Working right to left, the next number is your constant.
  • The next is the coefficient for x, the next is the coefficient for x squared and so on.
  • The degree of the quotient is one less than the degree of the dividend.
  • For example, if the degree of the dividend is 4, then the degree of the quotient is 3.

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Advantages of Synthetic Division

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  • Synthetic Division is a form of dividing polynomials. 
  • It is generally used to find out the zeros of the polynomial.
  • Linear factor of a polynomial is a one degree polynomial.
  • In synthetic division method, coefficient of the polynomials plays the most important part.
  • When calculating synthetic division the next degree coefficient is absent then we put zeroes at that place.
  • In the final equation, answer is always one degree less than the dividend.

Read More: Types of Functions


Things to Remember

  • Synthetic division method is a shorter form that involves the division of polynomials with another polynomial equation with degree one.
  • It involves the division of polynomials with the linear factor.
  • It is an error-prone method that can be solved without variables.
  • Linear Factor is in the form of ax+b.
  • The method is used to manually solve the Euclidean division of polynomials. 

Read More: Types of Relations


Sample Questions 

Ques: Divide 2x3-3x2 +4x-1 by x+1 (2 marks)

Ans: (x+1) / 2x3 -3x2+4x -1

Ques: Given f(x) = 3x3 +x2 -7x -5 and other expression is 3x – 5, find the result using remainder theorem? (2 marks)

Ans: f(x) = 3x3 +x2 -7x -5

0 is the remainder

Ques: Use Synthetic Division method to find out zeros of polynomial x3 +2x2 -5x -6 by x-2. (2 marks)

Ans: Write the coefficients of the polynomial

Here the remainder is 0 that means x-2 is a factor of the given polynomial.

Ques: Divide 2x3 -5x2 +3x +7 by x+ 2. (2 marks)

Ans: Putting the coefficients in the place 

9 is the remainder

(2x2 -x+1 +9by x-2 )

Ques:  Use synthetic division method to divide x3+x2−5x+3 is divided by x2+2x−3. (2 marks)

Ans: Put the coefficient of polynomials in synthetic form

Ques: Suppose x4+x3−2x2+x+1 is divided by x-1, the remainder obtained is 2 and the quotient is q(x). Find q(x).​ (2 marks)

Ans: x4+x3−2x2+x+1 is divided by x-1

Ques: When x3+5x2+ax−7 is divided by x−3, the remainder obtained is 47. Find a. (2 marks)

Ans:  Let f(x)=x3+5x2+ax−7 and required divisor is x−3

  • Now put x=3 in f(x)
  • f(3)=33+5(3)2+a(3)−7
  • 27+5(9)+3a−7
  • 27+45+3a−7 
  • 65+3a
  • But remainder = 47
  • So, 65+3a=47  as [p(3)=47] 
  • 3a=47−65
  • 3a=−18
  • a=−6

Ques: Consider the equation (x3 - 2x3 - 8x - 35). Divide the equation by (x - 5) using synthetic division method. (2 marks)

Ans: Given the equation (x3 - 2x3 - 8x - 35) .

  • Now divide it by x – 5 which is as follows:

Ques: The distance covered by erika in his car is given by the expression 9a- 39a - 30. The time taken by her to cover the required distance is given by the expression (a - 5). Find the speed of the car. (3 marks)

Ans: Speed of the car is given as the ratio of the distance to the time.

  • So to calculate the speed simly divide the distnace equation with time equation
  • Speed = (9a2 - 39a - 30)/(a - 5)

 Spped of the car is calculated as 9a + 6

Ques: Divide (6x2 + 7x - 20) by (2x + 5) using synthetic division method. (2 marks)

Ans: In this the expression (6x2 + 7x - 20) is divided by (2x + 5) which is as follows:

The quotient of the equation is 3x – 4

Ques: Divide x2 + 5x + 6 by x − 1 using synthetic division method. (2 marks)

Ans: In this the expression x2 + 5x + 6 is divided by x − 1 to obtain the quotient.

Ques: The volume of anu’s storage box is 8x+ 12x2 - 2x - 3. She knows that the area of the box is 4x- 1. What could be the height of the box. (3 marks)

Ans: As we known that Area = length × breadth 

  • we are given Area = 4x2 - 1.
  • The area is in the form of a2 - b= (a + b)(a - b)
  • As a result it can be expressed as, A = (2x + 1)(2x - 1)
  • V = l × b × h = A × h
  • h = (V/A) = (8x+ 12x2 - 2x - 3)/[(2x + 1)(2x - 1)]

Ques. Divide x3+2x2–3 is divided by x – 2. (2 marks)

Ans. Suppose f(x) = x3+2x2–3. 

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CBSE X Related Questions

  • 1.
    The dimensions of a window are $156\text{ cm} \times 216\text{ cm}$. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.


      • 2.
        An arc of length $2.2\text{ cm}$ subtends an angle $\theta$ at the centre of the circle with radius $2.8\text{ cm}$. The value of $\theta$ is

          • $50^\circ$
          • $60^\circ$
          • $45^\circ$
          • $30^\circ$

        • 3.
          Assertion (A) : The system of linear equations $3x - 5y + 7 = 0$ and $-6x + 10y + 14 = 0$ is inconsistent.
          Reason (R) : When two linear equations don't have unique solution, they always represent parallel lines.

            • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
            • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
            • Assertion (A) is true, but Reason (R) is false.
            • Assertion (A) is false, but Reason (R) is true.

          • 4.
            Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.


              • 5.
                PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.


                  • 6.
                    The value of p for which roots of the quadratic equation $x^2 - px + 6 = 0$ are rational, is

                      • $1$
                      • $-5$
                      • $25$
                      • $\sqrt{5}$

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