NCERT Solutions for Class 9 Maths Chapter 2 Polynomials Exercise 2.3 Solutions

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NCERT Solutions for Class 9 Maths Chapter 2 Polynomials Exercise 2.3 Solutions are based on the concept of Remainder Theorem.

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Check out NCERT Solutions for Class 9 Maths Chapter 2 Exercise 2.3 Solutions

Read More: NCERT Solutions For Class 9 Maths Chapter 2 Polynomials

Exercise Solutions of Class 9 Maths Chapter 2 Polynomials

Also check other Exercise Solutions of Class 9 Maths Chapter 2 Polynomials

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Chapter Related Topics
Polynomials	Remainder Theorem	Degree of polynomial
Polynomial Important Questions	Polynomials in One Variable	Synthetic Division
Remainder	Algebraic Identities	Cubic Polynomials

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CBSE X Related Questions

1.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.
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2.
\(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals
- \(\frac{21}{4} \text{ cm}\)
- \(\frac{28}{3} \text{ cm}\)
- \(\frac{12}{7} \text{ cm}\)
- \(5.5 \text{ cm}\)
View Solution
3.
The HCF of 960 and 432 is :
- 48
- 54
- 72
- 36
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4.
The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :
- 0
- 1
- 3
- 2
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5.
If the quadratic equation \(9x^2 + 8kx + 16 = 0\) has real and equal roots, then the value of k is
- 3
- –3
- –4
- \(\pm 3\)
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6.
A circle centered at (2, 1) passes through the points A(5, 6) and B(-3, K). Find the value(s) of K. Hence find length of chord AB.
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