NCERT Solutions for Class 9 Maths Chapter 2 Polynomials Exercise 2.3 Solutions

CBSE X Related Questions

  • 1.
    If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

      • \( -\frac{2}{3} \)
      • \( \frac{2}{3} \)
      • \( \frac{1}{3} \)
      • \( -\frac{1}{3} \)

    • 2.
      It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

        • \(\frac{\text{Perimeter of } \triangle ABC}{\text{Perimeter of } \triangle EDF} = \frac{AB}{ED}\)
        • \(\frac{AB}{ED} = \frac{AC}{EF}\)
        • \(\angle A = \angle D, \angle C = \angle F\)
        • \(\frac{AB + BC}{AC} = \frac{ED + DF}{EF}\)

      • 3.
        If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

          • \(4 \text{ cm}\)
          • \(4\sqrt{2} \text{ cm}\)
          • \(8 \text{ cm}\)
          • \(2\sqrt{2} \text{ cm}\)

        • 4.
          If roots of the quadratic equation \(x^2 - k\sqrt{3}x + 2 = 0\) are real and equal, then value of k is

            • \(-2\)
            • \(\sqrt{\frac{8}{3}}\)
            • \(1\)
            • \(2\)

          • 5.
            For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

              • \(0\)
              • \(\frac{80}{81}\)
              • \(1\)
              • \(\frac{82}{80}\)

            • 6.
              If for a data, median is 5 and mode is 4, then mean is equal to :

                • 7
                • 11
                • \(\frac{11}{2}\)
                • \(\frac{14}{3}\)

              Comments


              No Comments To Show