NCERT Solutions for Class 9 Maths Chapter 7 Triangles Exercise 7.3 Solutions

CBSE X Related Questions

  • 1.
    In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

      • $6$
      • $4$
      • $\pm 4$
      • $3$

    • 2.
      It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

        • \(\frac{\text{Perimeter of } \triangle ABC}{\text{Perimeter of } \triangle EDF} = \frac{AB}{ED}\)
        • \(\frac{AB}{ED} = \frac{AC}{EF}\)
        • \(\angle A = \angle D, \angle C = \angle F\)
        • \(\frac{AB + BC}{AC} = \frac{ED + DF}{EF}\)

      • 3.
        Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

          • \(10^{\circ}\)
          • \(60^{\circ}\)
          • \(45^{\circ}\)
          • \(100^{\circ}\)

        • 4.
          If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

            • \(\frac{7}{2}\)
            • \(\frac{6}{7}\)
            • \(\frac{-7}{6}\)
            • \(\frac{7}{6}\)

          • 5.
            For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

              • \(0\)
              • \(\frac{80}{81}\)
              • \(1\)
              • \(\frac{82}{80}\)

            • 6.
              The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

                • \((x + 2), (x - 5)\)
                • \((x + 5), (x - 2)\)
                • \((x + 1), (x - 5)\)
                • \((x - 1), (x + 2)\)

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