NCERT Solutions for Class 9 Maths Chapter 7 Triangles Exercise 7.5 Solutions

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NCERT Solutions for Class 9 Maths Chapter 7 Triangles Exercise 7.5 Solutions are based on the summary of previous exercises, like SAS Congruence Rule, ASA Congruence Rule, AAS Congruence Rule, SSS Congruence Rule, RHS Congruence Rule and Properties of Triangle.

Download PDF: NCERT Solutions for Class 9 Maths Chapter 7 Exercise 7.5 Solutions

Check out NCERT Solutions for Class 9 Maths Chapter 7 Exercise 7.5 Solutions

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Exercise Solutions of Class 9 Maths Chapter 7 Triangles

Also check other Exercise Solutions of Class 9 Maths Chapter 7 Triangles

Also Check:

Important Chapter Related Topics
Mid Point Theorem	Isosceles Triangle	Congruence of triangles
Class 9 Maths Chapter 7 Triangles MCQs	Properties of inequalities and triangles	Sides of a Triangle
Similar Figures	Triangles

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CBSE X Related Questions

1.
If the quadratic equation \(9x^2 + 8kx + 16 = 0\) has real and equal roots, then the value of k is
- 3
- –3
- –4
- \(\pm 3\)
View Solution
2.
The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :
- 0
- 1
- 3
- 2
View Solution
3.
\(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals
- \(\frac{21}{4} \text{ cm}\)
- \(\frac{28}{3} \text{ cm}\)
- \(\frac{12}{7} \text{ cm}\)
- \(5.5 \text{ cm}\)
View Solution
4.
In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.
View Solution
5.
If \(\alpha, \beta\) are the zeroes of the polynomial \(p(x) = x^2 - 3x - 1\), then find the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\).
View Solution
6.
The HCF of 960 and 432 is :
- 48
- 54
- 72
- 36
View Solution

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