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An algebraic statement of the second degree in x is called a quadratic equation. ax2 + bx + c = 0 is the standard form of the quadratic equation, where a, b are the coefficients, x is the variable, and c is the constant term. The coefficient of x2 is a non-zero term(a 0), which is the first criterion for an equation to be a quadratic equation. The x2 term is written first, then the x term, and finally the constant term when expressing a quadratic equation in standard form. The numeric values of a, b, and c are usually expressed as integral values rather than fractions or decimals.
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Key Takeaways: Quadratic, Root, equation, positive, negative, solution, discriminant, polynomial
Discriminant Formula for a Quadractic Equation
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The discriminant is the b2-4ac component of the quadratic formula beneath the square root sign. The discriminant indicates whether there are one, two, or no solutions available.
The solutions can be found by the formula
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
x is the solution.
b is the coefficient of the equation where the variable is in the power of 1.
c is the coefficient of the equation where the variable is in the power of 2.
a is the coefficient of the equation where the variable is in the power of 0.
Example using Discriminant Formula
Question: Find the discriminant of the equation x2 – 2x + 3 = 0. Determine the number of solutions to the equation.
Solution: x2 – 2x + 3 = 0
In the above equation,
a = 1 , b = -2 , and c = 3
The formula for discriminant is b2-4ac,
Δ = b2-4ac
=> Δ = 22 – 4(1)(3)
=>Δ = 4 – 12
Δ = -8 < 0
Since the value of the determinant is negative, the equation has no real solutions.
The video below explains this:
Quadratic Equations Detailed Video Explanation:
Also Read:
Importance of Discriminants
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The number of roots of a quadratic equation can be found using the discriminant. A discriminant might be positive, negative, or 0 in value. The nature of roots can be established by knowing the value of a determinant as follows:
- The quadratic equation has two actual and distinct solutions if the discriminant value is positive.
- The quadratic equation has only one or two real and equal solutions if the discriminant value is zero.
- The quadratic equation has no real solutions if the discriminant value is negative.
Things to Remember
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- An algebraic statement of the second degree in x is called a quadratic equation. ax2 + bx + c = 0 is the standard form of the quadratic equation, where a, b are the coefficients, x is the variable, and c is the constant term.
- The formula for discriminant is b2-4ac.
- If the determinant, Δ > 0, the equation will have 2 real solutions.
- If the determinant, Δ = 0, the equation will have 1 real solution.
- If the determinant, Δ < 0, the equation will have 2 conjugate complex solutions.
Also Read:
Sample Questions
Ques. Find the discriminant of the quadratic equation 5x2 + 3x + 2 = 0. Also, find out the nature of its roots. (3 marks)
Ans. The quadratic equation given is 5x2 + 3x + 2 = 0.
Matching this with the quadratic equation formula ax2 + bx + c = 0, we get the following values:
a = 5, b = 3, and c = 2.
Using the discriminant formula b2-4ac,
Δ = b2-4ac
= 32 - 4(5)(2)
= 9 - 40
= -31
Therefore, the discriminant is -31 which is a negative number and hence the given quadratic equation has two conjugate complex solutions.
Ques. Find the discriminant of the quadratic equation 3x2 + 4x + 5 = 0. Also, find out the nature of its roots. (3 marks)
Ans. The quadratic equation given is 5x2 + 3x + 2 = 0.
Matching this with the quadratic equation formula ax2 + bx + c = 0, we get the following values:
a = 5, b = 3, and c = 2.
Using the discriminant formula b2-4ac,
Δ = b2-4ac
= 52 - 4(5)(2)
= 25 - 40
= -15
Therefore, the discriminant is -15 which is a negative number and hence the given quadratic equation has two conjugate complex solutions.
Ques. Find the discriminant of the quadratic equation x2 + 4x - 5 = 0. Also, find out the nature of its roots. (3 marks)
Ans. The quadratic equation given is x2 + 4x - 5 = 0.
Matching this with the quadratic equation formula ax2 + bx + c = 0, we get the following values:
a = 1, b = 4, and c = -5.
Using the discriminant formula b2-4ac,
Δ = b2-4ac
= 42 - 4(1)(-5)
= 16 + 20
= 36
Therefore, the discriminant is 36 which is a positive number and hence the given quadratic equation has two real solutions.
The equation has the following two solutions:
(-4 36)/2 which gives x = 1 or x = -5
Ques. Find the discriminant of the quadratic equation 2x2 + 8x + 8 = 0. Also, find out the nature of its roots. (3 marks)
Ans. The quadratic equation given is 2x2 + 8x + 8 = 0.
Matching this with the quadratic equation formula ax2 + bx + c = 0, we get the following values:
a = 2, b = 8, and c = 8.
Using the discriminant formula b2-4ac
Δ = b2-4ac
= 82 - 4(2)(8)
= 0
Therefore, the discriminant is 0 which signifies that the given quadratic equation will have 1 real solution.
Ques. Find the discriminant of the quadratic equation 6x2 + 10x - 1 = 0. Also, find out the nature of its roots. (3 marks)
Ans. The quadratic equation given is 6x2 + 10x - 1 = 0.
Matching this with the quadratic equation formula ax2 + bx + c = 0, we get the following values:
a = 6, b = 10, and c = -1.
Using the discriminant formula b2-4ac
Δ = b2-4ac
= 102 - 4(6)(-1)
= 100 + 24
= 124 > 0
Therefore, the discriminant is 124 which is a positive number and hence the given quadratic equation has two real solutions.
Ques. Find the discriminant of the quadratic equation x2 - 4 = 0. Also, find out its roots. (3 marks)
Ans. The quadratic equation given is x2 - 4 = 0.
Matching this with the quadratic equation formula ax2 + bx + c = 0, we get the following values:
a = 1, b = 0, and c = -4.
Using the discriminant formula b2-4ac,
Δ = b2-4ac
= 02 - 4(1)(-4)
= 16
= 16 > 0
Therefore, the discriminant is 16 which is a positive number and hence the given quadratic equation has two real solutions.
The equation has the following two solutions:
(-0 16)/2 which gives x = 2 or x = -2
Ques. Find the discriminant of the quadratic equation 2x2 - 8x + 3 = 0. Also, find out the nature of its roots. (3 marks)
Ans. The quadratic equation given is 2x2 + 8x + 8 = 0.
Matching this with the quadratic equation formula ax2 + bx + c = 0, we get the following values:
a = 2, b = -8, and c = 3.
Using the discriminant formula b2-4ac,
Δ = b2-4ac
= (-8)2 - 4(2)(3)
= 40 > 0
Therefore, the discriminant is 40 which is a positive number and hence the given quadratic equation has two real solutions.









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