NCERT Solutions for Class 10 Maths Chapter 10 Circles Exercise 10.2

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NCERT Solutions for Class 10 Maths Chapter 10 Circles Exercise 10.2 Solutions are based on Number of Tangents from a Point on a Circle and Solved examples based on the concept. 

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CBSE X Related Questions

  • 1.
    There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

      • 144
      • 2
      • 420
      • 272

    • 2.
      In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is

        • $55^\circ$
        • $20^\circ$
        • $35^\circ$
        • $70^\circ$

      • 3.
        For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

          • \(0\)
          • \(\frac{80}{81}\)
          • \(1\)
          • \(\frac{82}{80}\)

        • 4.
          The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

            • \((x + 2), (x - 5)\)
            • \((x + 5), (x - 2)\)
            • \((x + 1), (x - 5)\)
            • \((x - 1), (x + 2)\)

          • 5.
            The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is

              • 2
              • \(-6\)
              • \(-2\)
              • 6

            • 6.
              If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

                • \(4 \text{ cm}\)
                • \(4\sqrt{2} \text{ cm}\)
                • \(8 \text{ cm}\)
                • \(2\sqrt{2} \text{ cm}\)

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