NCERT Solutions for Class 10 Maths Chapter 10 Circles Exercise 10.2

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NCERT Solutions for Class 10 Maths Chapter 10 Circles Exercise 10.2 Solutions are based on Number of Tangents from a Point on a Circle and Solved examples based on the concept.

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Exercise Solutions of Class 10 Maths Chapter 10 Circles

Also check other Exercise Solutions of Class 10 Maths Chapter 10 Circles

NCERT Solutions For Class 10 Maths Chapter 10 Exercise 10.1 Solutions

Also Check:

Chapter Related Topics
Circles Important Question	Circles Revision Notes	Chord of Circle
Circle Definition	Cyclic Quadrilateral	Semi Circle
Annulus	Tangent Circle Formula	Great Circle Formula
Circle Passing Through 3 Points	Circle Theorem	Arc

Also check:

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Math Formula	NCERT Solutions for Class 10 Maths	Algebra

CBSE X Related Questions

1.
The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is
- 2
- \(-6\)
- \(-2\)
- 6
View Solution
2.
For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is
- \(0\)
- \(\frac{80}{81}\)
- \(1\)
- \(\frac{82}{80}\)
View Solution
3.
If for a data, median is 5 and mode is 4, then mean is equal to :
- 7
- 11
- \(\frac{11}{2}\)
- \(\frac{14}{3}\)
View Solution
4.
Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is
- \(10^{\circ}\)
- \(60^{\circ}\)
- \(45^{\circ}\)
- \(100^{\circ}\)
View Solution
5.
The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are
- \((x + 2), (x - 5)\)
- \((x + 5), (x - 2)\)
- \((x + 1), (x - 5)\)
- \((x - 1), (x + 2)\)
View Solution
6.
If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :
- \( -\frac{2}{3} \)
- \( \frac{2}{3} \)
- \( \frac{1}{3} \)
- \( -\frac{1}{3} \)
View Solution

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NCERT Solutions for Class 10 Maths Chapter 10 Circles Exercise 10.2

Exercise Solutions of Class 10 Maths Chapter 10 Circles

CBSE X Related Questions

1.
The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is

2.
For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

3.
If for a data, median is 5 and mode is 4, then mean is equal to :

4.
Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

5.
The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

6.
If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

Similar Mathematics Concepts

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NCERT Solutions for Class 10 Maths Chapter 10 Circles Exercise 10.2

Exercise Solutions of Class 10 Maths Chapter 10 Circles

CBSE X Related Questions

1.The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is

2.For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

3.If for a data, median is 5 and mode is 4, then mean is equal to :

4.Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

5.The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

6.If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is

2.
For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

3.
If for a data, median is 5 and mode is 4, then mean is equal to :

4.
Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

5.
The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

6.
If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :