NCERT Solutions for class 11 Physics Chapter 6: Work, Energy, and Power

NCERT Solutions for Class 11 Physics Chapter 6 Work, Energy, and Power deals with the important concepts of the chapter. Work is referred to as the process of energy that is transferred to an object's motion by applying force. It is generally represented as the product of displacement and force. Power is the amount of energy that is transferred in a unit of time.

Unit 4 Chapter 6 Work, Energy, and Power along with Unit 5 and Unit 6 have a weightage of 17 marks in the Class 11 Physics Examination. The NCERT Solutions for Class 11 Physics Chapter 6 covers Conservative Force, Conservation Of Mechanical Energy, and Relation Between eV And Joule.

Download PDF: NCERT Solutions for Class 11 Physics Chapter 6

NCERT Solutions for Class 11 Physics Chapter 6

Class 11 Physics Chapter 6 – Concepts Covered

Work is said to be done when a force that is applied to the body displaces it through a certain distance in the direction of the applied force.

It is measured as the product of the force and the distance moved in the direction of the force applied, i.e., W = F.S

If an object undergoes a displacement ‘S’ along a straight line while it is acted on by a force F that makes an angle 0 with S. The work done would then be the product of the magnitude of displacement and the component of force in the direction of displacement.

$W = FScos \theta = \overrightarrow {F}.\overrightarrow {S}$

The energy possessed by a body is its capacity to do work. Energy is measured in the unit Joule.

Mechanical energy can be classified as Kinetic energy and Potential energy.

Kinetic Energy is the energy possessed by a body by virtue of its motion. For an object having mass m and velocity v, the kinetic energy is given by:

Kinetic Energy or KE = ½ mv²

Potential Energy is the energy of a body by virtue of its position or condition.

Potential energy is of two types – gravitational and elastic potential energy.

Class 11 Physics Chapter 6 Related Guides:

Heat	Principle of Conservation of Energy	Elastic and Inelastic Collisions
Pulley	Unit of Power	Types of Energy
Elastic Collision	Unit of Work	Derivation of Kinetic Energy
Pulley System	Types of Springs	Derivation of Work Energy Theorem
Linear Momentum Formula	Mechanical Advantage Formula	Difference between Kinetic and Potential Energy

Class 11 Physics Study Guides:

NCERT Solutions for Class 11 Physics	Class 11 Physics Notes	Physics Study Notes
Difference between in Physics	Derivations in Physics	SI Units in Physics
Relation between articles in Physics	Physics Constants	Physics Formula

CBSE CLASS XII Related Questions

1.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

5 V
3.5 V
2.5 V
Zero V

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2.
Draw the plot of potential energy of a pair of nucleons as a function of their separation. Write two important conclusions that can be drawn from this plot.

View Solution

3.
A magnet held vertically, with its north pole down, is dropped along the axis of a closed solenoid placed vertically on a table. If the observer looks down from the top,

the induced current will flow in the anticlockwise direction.
the induced current will flow in the clockwise direction.
no induced current will flow in the solenoid.
the magnet will fall with a constant velocity.

View Solution

4.
A parallel beam of monochromatic light falls normally on a single slit of width $a$ and a diffraction pattern is observed on a screen placed at distance $D$ from the slit. Explain:
(I) the formation of maxima and minima in the diffraction pattern, and
(II) why the maxima go on becoming weaker and weaker with its increasing number $n$.

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5.
A wire of length $L$ is bent round into (i) a square coil having $N$ turns and (ii) a circular coil having $N$ turns. The coil in both cases is free to turn about a vertical axis coinciding with the plane of the coil, in a uniform, horizontal magnetic field and carry the same currents. Find the ratio of the maximum value of the torque acting on the square coil to that on the circular coil.

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6.
Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

$\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (\hat{i} - \hat{j})$
$\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (-\hat{i} - \hat{j})$
$\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (\hat{i} - \hat{j})$
$\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (-\hat{i} - \hat{j})$

View Solution

NCERT Solutions for class 11 Physics Chapter 6: Work, Energy, and Power

NCERT Solutions for Class 11 Physics Chapter 6

Class 11 Physics Chapter 6 – Concepts Covered

CBSE CLASS XII Related Questions

1.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

2.
Draw the plot of potential energy of a pair of nucleons as a function of their separation. Write two important conclusions that can be drawn from this plot.

3.
A magnet held vertically, with its north pole down, is dropped along the axis of a closed solenoid placed vertically on a table. If the observer looks down from the top,

6.
Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

Similar Physics Concepts

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NCERT Solutions for class 11 Physics Chapter 6: Work, Energy, and Power

NCERT Solutions for Class 11 Physics Chapter 6

Class 11 Physics Chapter 6 – Concepts Covered

CBSE CLASS XII Related Questions

1.A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

2.Draw the plot of potential energy of a pair of nucleons as a function of their separation. Write two important conclusions that can be drawn from this plot.

3.A magnet held vertically, with its north pole down, is dropped along the axis of a closed solenoid placed vertically on a table. If the observer looks down from the top,

6.Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

2.
Draw the plot of potential energy of a pair of nucleons as a function of their separation. Write two important conclusions that can be drawn from this plot.

3.
A magnet held vertically, with its north pole down, is dropped along the axis of a closed solenoid placed vertically on a table. If the observer looks down from the top,

6.
Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be: