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NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Exercise 11.3 is given as a pdf in the article below. Exercise 11.3 discusses the following important topics:
The exercise gives an introduction to basic three-dimensional shapes and illustrates with examples the formula for evaluating the surface area of a cube, cuboid, and cylinder.
Download PDF of NCERT Solutions for Class Chapter 11 Mensuration Exercise 11.3
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Example From Chapter 11 Mensuration
| Ques. A cylinder whose base radius is 7cm has a height of 20cm. Find the total surface area of the cylinder. Soln: The total surface area of a cylinder is given by: 2ℼr(r + h) Given, Radius, r = 7 cm Height, h = 20 cm Therefore, The total surface area= 2 ×ℼ × 7 (7 + 20) = 1188 cm2 |
Also Read
| Class 8 Chapter 11 Mensuration | ||
|---|---|---|
| Mensuration Formula | Surface Area and Volumes | Geometry Formula |
| Basic Geometrical Shapes | Cuboid | Quadrilateral Formulas |
Also Read
| CBSE Class 8 Maths Study Guide | ||
|---|---|---|
| NCERT Solutions for Class 8 Maths | Maths MCQs | Volume and Capacity |
| Maths Study Notes | Maths Formula | Angle Sum Property of Quadrilaterals |
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