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NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Exercise 11.4 covers basic concepts of surface and volume of three-dimensional solids. This exercise of Chapter 11 Mensuration is based on the evaluation of the volume of a cube, the volume of a cuboid, and the volume of a cylinder.
Concepts of volume and capacity are briefly discussed with relevant examples. The NCERT Solutions for Chapter 11 Mensuration are provided as a pdf in the article.
Download PDF of NCERT Solutions for Class Chapter 11 Mensuration Exercise 11.4
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Example From Chapter 11 Mensuration
| Ques. If the total surface area of a cube is 486 cm2. Find its volume. Soln: Total surface area of a cube = 6(length)2 Therefore, it is given, 486 = 6(side)2 (Side)2= 486/6 (Side)2 = 81cm Therefore, Length of each side =9cm Volume of a cube =(side)3 Therefore, Volume = (9)3 Volume of the cube = 729 cm3 |
Also Read
| Class 8 Chapter 11 Mensuration | ||
|---|---|---|
| Mensuration Formula | Angle Sum Property of Quadrilaterals | LSA & TSA of a Cylinder |
| Area Vs Volume | Cuboid | Area of Hollow Cylinder |
Read More
| CBSE Class 8 Maths Study Guide | ||
|---|---|---|
| NCERT Solutions for Class 8 Maths | Maths MCQs | Maths Study Notes |
| Maths Formula | Volume and Capacity | Surface Area and Volumes |
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