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Our Earth contains more than hundred elements till and simplest classification of elements till now is basis on whether an element is metal or non-metal.
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Keyterms: Metal, Non-metal, Element, Mercury, Lithium, Potassium, Gallium, Caesium, Alkali, s-block
What are Metals and what are their properties?
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Basically, Metals comprises of those elements that are generally in solid state (except Mercury which is liquid at room temperature) and possess following physical properties:
- Very Hard (except Alkali metals found in s-block such as Lithium, Potassium, etc.)
- High Melting and Boiling points (except Gallium & Caesium which have very low melting point)
- Lustrous
- Malleable
- Ductile
- Excellent conductors of heat and electricity
Most important chemical property is that metals usually form electropositive ions during reactions and therefore, acts as reducing agents.
For e.g., Sodium, Potassium, Calcium, Magnesium, etc.
Chemical Reactions of Metals
Metals are known to be highly electropositive in nature and hence, lose electrons very easily during reactions that makes them reactive.
What are Non-Metals and what are their properties?
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Non-Metals are usually in solid and gaseous form (except Bromine which is liquid) and possess following physical properties:
- Brittle
- Soft in nature (except Diamond which is an allotrope of Carbon and is hardest substance on Earth)
- Insulators or poor conductors of heat and electricity (except Graphite which is an allotrope of Carbon and very good conductor)
- Amorphous
- Non-malleable and non-ductile
- Low melting and boiling points (except Diamond which is an allotrope of Carbon and has very high melting and boiling point)
Most important chemical property is that Non-Metals usually forms electronegative ions during reactions and therefore, acts as an oxidizing agent.
For e.g., Carbon, Sulphur, Hydrogen, Phosphorous, etc.
Why metals are electropositive?
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Let us look at the table mentioning atomic properties of some metals below to find an answer:
| Name of Metal | Atomic Number | Number of electrons in shells | |||
|---|---|---|---|---|---|
| K | L | M | N | ||
| Sodium (Na) | 11 | 2 | 8 | 1 | |
| Magnesium (Mg) | 12 | 2 | 8 | 2 | |
| Aluminium (Al) | 13 | 2 | 8 | 3 | |
| Potassium (K) | 19 | 2 | 8 | 8 | 1 |
| Calcium (Ca) | 20 | 2 | 8 | 8 | 2 |
By analyzing this table, we can clearly see metals are not stable as they don’t contain 8 electrons in last orbital to complete octet and become stable. We can see 1 or 2 or at last 3 electrons in last orbital of every metal. We know reactions happen by elements to make themselves more stable and stability is defined by OCTET RULE till now what we have studied. So, to obtain octet in their last orbital, they have to either lose electrons or obtain electrons. But, losing is far better than gaining as they need more than 4 electrons whereas metals can lose at most electrons. So, this is the reason why metals lose their electron as it saves their energy to become stable and therefore, making them electropositive during reactions.
Now, we know that why metals are electropositive and reactive, we will see reactions with various reagents:
- Reaction of metals with air:
Metals are reactive in nature and therefore, forms oxides when exposed to air. Some metals such as Sodium and Potassium even burns in air forming oxides. While other metals form oxide layer that prevents the metal from further oxidation. Copper does not burn, but the hot metal is coated with a black coloured layer of Copper(II) oxide. Even at high temperatures, Silver and gold do not react with oxygen.
Metal + Oxygen = Metal Oxide
For e.g.
When Sodium [Na] reacts with oxygen, it forms Sodium Peroxide in general form.
2Na + O2 → Na2O2
When Copper [Cu(II)] reacts with oxygen, it forms Copper(II) oxide.
2Cu + O2 → 2CuO
Metal oxides are basic in nature and mostly insoluble in water but some soluble oxides react with water to form hydroxides (aqueous solution). There are amphoteric oxides too which can react with acid as well as base to such as Zinc oxide and Aluminum oxide.
Aluminum oxide reacts with Sodium Hydroxide to form Sodium Aluminate and water.
Al2O3 + 2NaOH → 2NaAlO2 + H2O
Aluminum oxide reacts with Hydrochloric acid to form Aluminum Chloride and water.
Al2O3 + 6HCl → 2AlCl3 + H2O
- Reaction with metals with water:
Hydrogen gas is liberated when Metals reacts with water and form hydroxides.
For e.g.
Calcium forms Calcium Hydroxide and Hydrogen by reacting with water.
Ca + 2H2O → Ca(OH)2 + H2
- Reaction of metals towards dihydrogen:
Metal Hydrides are formed when Metals reacts with dihydrogen.
For e.g.
Alkali metals react in following way:
2M + H2 → 2M+H-
- Reaction of metals with Halogens:
Metals react with halogens to form halides which are ionic compounds.
For e.g.
Sodium reacts with Chlorine to form Sodium Chloride.
2Na + Cl2 → 2NaCl
- Reaction of metals with acids:
Metals react with dilute acids to form metal salt and liberates hydrogen. But, in case of Nitric acid, even liberated hydrogen is oxidized to water due to strong oxidizing nature of Nitric acid. But exceptions are always there as Manganese and Magnesium only liberates hydrogen when reacted with dilute Nitric acid.
For e.g.
Sodium reacts with dilute Sulphuric acid to form Sodium Sulphate and Hydrogen gas.
2Na(s) + H2SO4 (aq) → Na2SO4 (aq) + H2 (g)
- Reactions of metals with another metal salts:
Metals react with other metal salts according to reactivity series which is mentioned below:
Through this table, we can see that less reactive metals get replaced by high reactive metals in reaction.
Metal A + Salt Solution of Metal B = Salt solution of Metal A + Metal B
For e.g.
Iron is more electropositive than Copper and therefore, replace it in this reaction to form Iron Sulphate.
Fe + CuSO4 → FeSO4 + Cu
Why non-metals are electronegative?
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Let us look at the table mentioning atomic properties of some non-metals below to find an answer:
| Name of Non-Metal | Atomic Number | Number of electrons in shells | |||
|---|---|---|---|---|---|
| K | L | M | N | ||
| Nitrogen (N) | 7 | 2 | 5 | ||
| Oxygen (O) | 8 | 2 | 6 | ||
| Fluorine (F) | 9 | 2 | 7 | ||
| Phosphorous (P) | 15 | 2 | 8 | 5 | |
| Sulphur (S) | 16 | 2 | 8 | 6 | |
By analyzing above table, we can clearly see that non-metals require electrons to achieve stability and complete octet as losing 5 or more electrons will involve more energy than gaining just 1 to 3 electrons during reactions and therefore, non-metals act as electronegative ions during reactions.
But non-metals show very diverse behavior and therefore, their reactions are different too.
- Reaction of non-metals with air:
Non-metals reacts with oxygen to form acidic oxides.
For e.g.
Carbon reacts with oxygen to form Carbon Dioxide.
C + O2 → CO2
Phosphorous reacts with Oxygen to form Phosphorous Pentoxide.
P4 + 5O2 → 2P2O5
- Reaction of non-metals with water:
Non-metals never reacts with water as they form electronegative and cannot form oxides as well as hydroxides and even reaction cannot be done at higher temperatures.
- Reaction of non-metals with dihydrogen:
Since, hydrogen is itself a non-metal and therefore, they form covalent bonds and hence, hydrides.
For e.g.
Nitrogen and Hydrogen combines to form most important chemical Ammonia.
N2 + 3H2 → 2NH3
- Reaction of non-metals with halogen:
Non-metals form covalent bond with halogens to form halides. There are various compounds for same halogen as different non-metals possess different electronegativity. These halides undergo hydrolysis too.
For e.g.
Phosphorous reacts with Chlorine to form Phosphorous Trichloride and Phosphorous Pentachloride.
P4 + 6Cl2 → 4PCl3
P4 + 10Cl2 → 4PCl5
- Reaction of non-metals with acids:
Non-metals don’t react with dilute acids as they cannot replace hydrogen ion and cannot liberate dihydrogen gas.
Ionic Compounds
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Now, we know that metals form electropositive ions and non-metals form electronegative ions and therefore, when metal and non-metal react, generally ionic compounds formed.
Metals behaves as oxidizing agents and non-metals as reducing agents to form ionic compounds.
For e.g.
Zn + S → Zn2+ + S2- (ZnS)
2Mg + Cl2 → 2Mg2+ + 2Cl- (MgCl2)
Occurrence of metals
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Metals are most important elements but since, they are highly reactive and forms salts. Extracting metals back to pure form is not an easy task and therefore requires knowledge of metallurgical concepts.
There are various metals and extraction techniques that is shown in figure.
We can see that highly reactive metals need electrolytic process and medium reactivity metals needs carbon reduction technique to extract pure metal. Since, Gold and Silver are least reactive metals and therefore, they are found as pure metals only in ores too.
Reactions that involve extraction of metals are written as follows:
For Mercury:
2HgS (s) + 3O2 (g) (heated) → 2HgO (s) + 2SO2 (g)
2HgO (l) (heated) → 2Hg (l) + O2 (g)
For Manganese:
3MnO2 (s) + 4Al (s) → 3Mn (l) + 2Al2O3
For extraction through electrolysis, setup is required as shown in figure.
This is also known as Hall-Heroult process. Reaction for Aluminum extraction which is done at cathode is shown below:
Cathode reaction: Al3+ (melt) + 3e- → Al (l)
Anode reaction: C + 1/2O2- → CO/CO2 + 2/4e-
Sample Questions
Question: (a) Carbon cannot reduce the oxides of Sodium, Aluminum and Magnesium to their respective metals. Why?
(b) Where are these metals placed in reactivity series?
(c) How are these metals obtained from their ores? (5 Marks)
Answer:
- Sodium, Aluminum and Magnesium are known to be highest reactive elements in reactivity series and these are highly reactive than carbon and therefore, carbon cannot reduce these metals. Secondly, Carbon is non-metal which is known as oxidizing agent not reducing agent.
- Reactivity order is as follows: K > Na > Mg
- These metals are obtained from ores through process of electrolysis as highest reactive metals are extracted through that process only.
At cathode site, these metals liberated as follows:
K+ + e- = K
Na+ + e- = Na
Mg2+ + 2e- = Mg
Question: The compound obtained on reaction of iron with steam are: (1 Mark)
(a) Fe2O3
(b) Fe3O4
(c) FeO
(d) Fe2O3 & Fe3O4
Answer: Since, we know that
3Fe(s) + 4H2O → Fe3O4 (Fe2O3 + FeO) + H2
Hence, answer is (b)
Question: An element ‘X’ reacts with air to give a compound with high melting point. This compound is also soluble in water. An element ‘X’ is likely to be: (1 Mark)
(a) Iron (b) Calcium
(c) Silicon (d) Carbon
Answer. We are given hint that compound is having high melting point and compound is soluble in water. Ionic compounds possess both these properties and therefore, X should be metal only. So, we left with two options i.e., Calcium and Iron. Now, both of these form oxides but since, reactivity of calcium is high and therefore, it will form stronger ionic compound with oxygen and more stable compound means higher melting point.
Therefore, we will choose Calcium in front of iron due to its more reactivity i.e., b.) option.
Question: What happens when (Write the balanced equation involved)
(a) Copper is heated in air
(b) Aluminium oxide is reacted with hydrochloric acid
(c) Potassium reacts with water
(d) Cinnabar is heated in air
(e) Aluminium oxide reacts with sodium hydroxide (5 Marks)
Answer. a.) 2Cu + O2 = 2CuO
b.) Al2O3 + 6HCl = 2AlCl3 + 3H2O
c.) 2K + 2H2O = 2KOH + H2
d.)2HgS + 3O2 = 2HgO+2SO2
e.) Al2O3 + 2NaOH = 2NaAlO2 + 3H2O
Question: Consider the following statements about an element ‘X’ with number of protons 13.
(A) It forms amphoteric oxide
(B) Its valency is three
(C) It makes trichloride as product when reacts with Chlorine
The correct statements(s) is/are
(a) only (A)
(b) only (B)
(c) (A) and (C)
(d) (A), (B) and (C) (1 Mark)
Answer. Protons are 13 and its clearly Aluminium according to atomic number. We know that Al forms amphoteric oxides, it forms Al3+ electropositive ion as its valency is three and balanced equation for reaction of Al and Cl is
2Al + 3Cl2 = 2AlCl3
Hence, all of the things are right and answer is (d).
Question: (a) Write two properties of gold which make it the most suitable metal for ornaments.
(b) Name two metals which are the best conductors of heat.
(c) Name two metals which melt when you keep them on your palm. (3 Marks)
Answer.
a) It is malleable and ductile.
b) Silver and Gold.
c) Gallium and Caesium.
Question: Two ores X and Y were taken. On heating these ores, it was observed that (5 Marks)
(a) ore X gives CO2 gas, and
(b) ore Y gives SO2 gas.
Write steps to convert these ores into metals, giving chemical equations of the reactions that take place.
Answer. Since, ore X is giving carbon dioxide, it needs to be a carbonate ore of metal X and similarly sulphide ore of element Y is there.
Therefore, for carbonate ore, calcination will be done i.e.
XCO3 (heated) = XO + CO2
After that, oxide is reduced by C(Coke)
2XO + C = 2X + CO2
For sulphide ore, roasting is done i.e.
2YS + 3O2 = 2YO + 2SO2
And it is also reduced with C
2YO + C = 2Y + CO2
Question: Give reasons: (3 Marks)
(a) Platinum, gold and silver are used to make jewellery
(b) Metals like sodium and potassium are stored under oil.
Answer. (a) Because, they are least reactive among metals and highly ductile as well as malleable to be able to turn into ornaments.
(b) Metals like Na and K burns vigorously on exposure to air forming their oxides due to their very high reactivity. To prevent this incident, these are stored under oil so that they don’t get exposed to air and remain in their pure form.
Question: Silver articles become black when kept in open for some time, whereas copper vessels lose their shiny brown surfaces and gain a green coat when kept in open. Name the substances present in air with which these metals react and write the name of the products formed. (3 Marks)
Answer. Silver as well as Copper forms oxides when kept in open for some time due to presence of air or we can say Oxygen as metals are prone to react with air but these metals react very calmly and protective oxide layer helps in preventing further oxidation of these metals.
4Ag + O2 = 2Ag2O (Silver oxide which is black in color)
2Cu + O2 = 2CuO (Copper oxide which is green in colour)
Question: Name the ore of mercury. With the help of balanced chemical equations, explain the process of extraction of mercury from its ore. (3 Marks)
Answer. Cinnabar (HgS) is a major ore of Mercury. Since, Mercury is very less reactive, its reduction takes place by heating only and then further reduces to Mercury very easily.
2HgS (s) + 3O2 (g) (heated) → 2HgO (s) + 2SO2 (g)
2HgO (l) (heated) → 2Hg (l) + O2 (g)








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