Differentiation

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Jasmine Grover

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Differentiation describes the instantaneous rate of change of a function with respect to its independent variable. 

  • The basic definition of differentiation involves taking the limit of a difference quotient as the change in the independent variable approaches zero. 
  • This definition can be extended to functions of multiple variables, leading to the concept of partial differentiation. 
  • There are also various rules and techniques for differentiating functions of different types, including polynomials, trigonometric functions, and exponential functions.

Differentiation is a key tool used to solve a wide range of problems across various fields, including physics, economics, engineering, and more. It is used to model and analyze change, growth, and decay in real-world phenomena, such as the speed of a moving object, the rate of population growth, and the decay of radioactive materials.

Key Terms: Derivative, Function, Constant, Trigonometric, Calculus, Limits, Continuity, Logarithmic, Exponential


What is Differentiation?

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Differentiation is the process of finding the derivative of a function, which describes the rate at which the output of the function changes with respect to its input. 

  • Differentiation helps us understand how quickly a function is changing at any given point.
  • The derivative of a function is defined as the limit of the ratio of the change in the output of the function to the change in its input, as the change in the input approaches zero. 
  • Geometrically, the derivative represents the slope of the tangent line to the function at a given point. 
  • The process of differentiation enables us to calculate this slope and, in turn, to analyze the behavior of the function at that point.

Differentiation

Differentiation

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Continuity and Differentiability Detailed Video Explanation:

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Derivatives Definition and Formula

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The derivative of a function is a measure of how fast the function changes at any given point. It is defined as the limit of the difference quotient as the change in the input variable approaches zero.

More precisely, let f(x) be a function of x. The derivative of f(x) at a point x=a is denoted by f'(x) or dy/dx evaluated at x=a. It is defined by the following limit:

f'(x) = lim [f(x+h) - f(x)]/h as h approaches 0

This limit represents the instantaneous rate of change of f(x) at the point x=a. 

Derivative of Function As Limits

The derivative tells how much the output of the function changes for a small change in the input. The smaller the change in the input, the closer we get to the exact rate of change at the point.

The expression of the derivative using limits can be derived as follows:

f'(x) = lim [f(x+h) - f(x)]/h as h approaches 0

= lim [f(x+h) - f(x)]/(h(x+h-x)) as h approaches 0

= lim [f(x+h) - f(x)]/h . lim 1/(x+h-x) as h approaches 0

= lim [f(x+h) - f(x)]/h . lim 1/h as h approaches 0

= lim [f(x+h) - f(x)]/h . lim 1/h as h approaches 0

= lim [f(x+h) - f(x)]/h . 1 as h approaches 0

= lim f(x+h)/h - lim f(x)/h as h approaches 0

= f'(x) - 0 as h approaches 0

Therefore, the derivative can be expressed mathematically using the limit definition as:

f'(x) = lim h→0 [f(x+h) - f(x)]/h


Notations

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The derivative of a function f(x) can be denoted in different notations depending on the context and the convention used. Some of the most common notations for derivatives are:

  • Leibniz notation: This notation uses the symbol dy/dx to represent the derivative of y with respect to x. If y = f(x), then dy/dx represents the derivative of f(x) with respect to x.
  • Newton notation: This notation uses a dot above the function to denote the derivative. For example, if y = f(x), then ẏ represents the derivative of f(x) with respect to x.
  • Lagrange notation: This notation uses the symbol f'(x) to represent the derivative of f(x) with respect to x. If y = f(x), then f'(x) represents the derivative of f(x) with respect to x.
  • Prime notation: This notation uses a single quote mark (') to represent the derivative. For example, if y = f(x), then y' represents the derivative of f(x) with respect to x.
  • Operator notation: This notation uses the symbol D to represent the derivative operator. For example, if y = f(x), then Dy represents the derivative of f(x) with respect to x.

Conditions for a Function to be Differentiable

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The main conditions for a function to be differentiable are:

  • Continuity:

A function must be continuous at the point where it is being differentiated. This means that the function has no breaks, jumps, or holes at that point. In other words, the limit of the function as x approaches the point must exist and be equal to the value of the function at that point.

  • Existence of limit:

The limit of the difference quotient must exist as x approaches the point of differentiation. That is the limit:

lim (h -> 0) [f(x+h) - f(x)]/h

must exist, where h is a small positive number.

  • Existence of derivative

The limit of the difference quotient as h approaches 0 must exist. This limit is the definition of the derivative of the function at the point x. If the limit exists, the function is said to be differentiable at that point.

If a function satisfies these three conditions at a point, it is said to be differentiable at that point. If a function is differentiable at every point in its domain, it is said to be a differentiable function. 


Differentiation of Linear and Non-Linear Functions

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Linear functions are functions of form f(x) = mx + b, where m and b are constants. The derivative of a linear function is a constant value, which is equal to the slope of the function. For example, the derivative of the function f(x) = 2x + 3 is 2, which represents the slope of the line. The same is true for any other linear function.

Nonlinear functions, on the other hand, do not have a constant rate of change. The derivative of a nonlinear function can be a complex function, depending on the form of the function. The process of finding the derivative of a nonlinear function can be more challenging and requires the use of more advanced techniques, such as the chain rule, product rule, or quotient rule.

Some common examples of nonlinear functions include polynomial functions, trigonometric functions, exponential functions, logarithmic functions, and inverse functions. For example, the derivative of the function f(x) = x3 is f'(x) = 3x2, which is a nonlinear function. Similarly, the derivative of the function g(x) = sin(x) is g'(x) = cos(x), which is also a nonlinear function.


Differentiation of Elementary Functions

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Elementary functions include basic mathematical functions such as constant functions, polynomials, exponential functions, logarithmic functions, and trigonometric functions. 

  • Constant functions:

Constant functions are elementary functions and their derivative is always zero. A constant function is a function of the form f(x) = c, where c is a constant. The derivative of a constant function is given by:

f'(x) = 0

For example, if f(x) = 5, then f'(x) = 0. This means that the slope of a constant function is always zero, and its graph is a horizontal line.

  • Power functions:

A power function is a function of the form f(x) = xn, where n is a constant. To find the derivative of a power function the power rule is given by:

f'(x) = nx(n-1)

For example, if f(x) = x3, then f'(x) = 3x2.

  • Exponential functions:

An exponential function is a function of the form f(x) = ax, where a is a constant. The derivative of an exponential function is given by:

f'(x) = ax * ln(a)

For example, if f(x) = ex, then f'(x) = ex.

  • Logarithmic functions:

A logarithmic function is a function of the form f(x) = loga(x), where a is a constant. The derivative of a logarithmic function is given by:

f'(x) = 1/(x*ln(a))

For example, if f(x) = log2(x), then f'(x) = 1/(x*ln(2)).

  • Trigonometric functions:

Trigonometric functions are functions of the form f(x) = sin(x), cos(x), or tan(x). The derivatives of these functions are given by:

f'(x) = cos(x) (for sin(x))

f'(x) = – sin(x) (for cos(x))

f'(x) = sec2(x) (for tan(x))

For example, if f(x) = sin(x), then f'(x) = cos(x).

  • Inverse trigonometric functions:

Inverse trigonometric functions are functions of the form f(x) = sin-1(x), cos-1(x), or tan-1(x). The derivatives of these functions are given by:

f'(x) = 1/sqrt(1-x2) (for sin-1(x))

f'(x) = -1/sqrt(1-x2) (for cos-1(x))

f'(x) = 1/(1+x2) (for tan-1(x))

For example, if f(x) = sin-1(x), then f'(x) = 1/sqrt(1-x2).

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Rules of Differentiation

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  • Constant Rule:

The constant rule is used to find the derivative of a constant. It states that:

d/dx [c] = 0

where c is a constant. This rule simply states that the derivative of a constant is zero.

For example, if f(x) = 5, then f'(x) = 0.

The constant rule is often used in conjunction with other rules of differentiation to find the derivative of more complex functions.

  • Sum Rule:

The sum rule is used to find the derivative of a sum of two or more functions. It states that:

d/dx [f(x) + g(x)] = f'(x) + g'(x)

For example, if f(x) = x2 and g(x) = 3x, then:

(f(x) + g(x))' = 2x + 3

  • Difference Rule:

The difference rule is used to find the derivative of a difference of two functions. It states that:

d/dx [f(x) - g(x)] = f'(x) - g'(x)

For example, if f(x) = x2 and g(x) = 3x, then:

(f(x) - g(x))' = 2x - 3

  • Power Rule:

The power rule is used to find the derivative of a function raised to a power. It states that:

d/dx [xn] = n*x(n-1)

For example, if f(x) = x3, then f'(x) = 3x2.

  • Product Rule:

The product rule is used to find the derivative of a product of two functions. It states that:

d/dx [f(x)*g(x)] = f'(x)*g(x) + f(x)*g'(x)

For example, if f(x) = x2 and g(x) = sin(x), then:

(f(x)g(x))' = 2xsin(x) + x2*cos(x)

  • Quotient Rule:

The quotient rule is used to find the derivative of a quotient of two functions. It states that:

d/dx [f(x)/g(x)] = [f'(x)*g(x) - f(x)*g'(x)]/g(x)2

For example, if f(x) = x2 and g(x) = sin(x), then:

(f(x)/g(x))' = (2xsin(x) - x2cos(x))/(sin(x)2)

  • Chain Rule:

The chain rule is used to find the derivative of a composition of two functions. It states that:

d/dx [f(g(x))] = f'(g(x))*g'(x)

For example, if f(x) = sin(x) and g(x) = x2, then:

f(g(x)) = sin(x2)

(f(g(x)))' = cos(x2)*2x


Differentiation of Special Functions

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There are two special methods for differentiating functions that can be difficult to differentiate using the standard rules.

  • Implicit Differentiation:

Implicit differentiation is a method used to find the derivative of an implicitly defined function. An implicit function is a function where one variable cannot be easily solved for in terms of the other variable(s). To find the derivative of an implicitly defined function, differentiate both sides of the equation with respect to the independent variable.

For example, equation of a circle:

x2 + y2 = r2

We can implicitly define y as a function of x, i.e. y(x). Differentiating both sides with respect to x, we get:

2x + 2y(dy/dx) = 0

Solving for dy/dx, we get:

dy/dx = – x/y

  • Logarithmic Differentiation:

Logarithmic differentiation is a method used to find the derivative of a function that can be written as a product or quotient of simpler functions. The basic idea is to take the logarithm of both sides of the equation and then differentiate implicitly.

Example: Write this function, f(x) = x(2/3) * (x2 + 1)4 as a product of two simpler functions

Solution: f(x) = (x(2/3)) * ((x2 + 1)4)

Taking the natural logarithm of both sides of the equation, we get:

ln(f(x)) = ln(x(2/3)) + ln((x2 + 1)4)

Using the properties of logarithms, we can simplify this expression:

ln(f(x)) = (2/3)ln(x) + 4ln(x2 + 1)

Differentiating both sides with respect to x and using the chain rule, we get:

f'(x)/f(x) = (2/3)1/x + 4(2x)/(x2 + 1)

Solving for f'(x), we get:

f'(x) = f(x) * [(2/3)*1/x + 8x/(x2 + 1)]

Higher Order Differentiation: Higher order differentiation is the process of taking the derivative of a function multiple times. The result is known as the nth derivative of the function.

The nth derivative of a function f(x) is denoted as f^(n)(x), where n is the order of the derivative. The first derivative is denoted as f'(x), the second derivative is denoted as f''(x), and so on.

To find the nth derivative of a function, we differentiate the function n times using the standard rules of differentiation. For example, the second derivative of a function f(x) is found by taking the derivative of the first derivative:

f''(x) = [d/dx] [f'(x)]

Example: Find the third derivative of the function f(x) = x4.

Solution: First, take the first derivative:

f'(x) = 4x3

Next, we take the second derivative:

f''(x) = [d/dx] [4x3] = 12x2

Finally, we take the third derivative:

f'''(x) = [d/dx] [12x2] = 24x

So the third derivative of f(x) = x4 is f'''(x) = 24x.

Partial Differentiation: Partial differentiation is the process of taking the partial derivative of a multivariable function with respect to one of its variables, while holding all other variables constant. It is a fundamental concept in multivariable calculus and is used extensively in physics, economics, engineering, and other fields.

The partial derivative of a function f(x,y) with respect to x, denoted as ∂f/∂x or f_x, is found by differentiating f(x,y) with respect to x while treating y as a constant. Similarly, the partial derivative of f(x,y) with respect to y, denoted as ∂f/∂y or f_y, is found by differentiating f(x,y) with respect to y while treating x as a constant.

Example: Find the first-order partial derivatives of the function f(x,y,z) = 3x2y + yz3 with respect to x, y, and z:

Solution: ∂f/∂x = 6xy (differentiate 3x2y with respect to x, treating y and z as constants)

∂f/∂y = 3x2 + z3 (differentiate 3x2y with respect to y, treating x and z as constants, and differentiate yz3 with respect to y, treating z as a constant)

∂f/∂z = 3yz2 (differentiate yz3 with respect to z, treating x and y as constants)

So the first-order partial derivatives of f(x,y,z) with respect to x, y, and z are 6xy, 3x2 + z3, and 3yz2, respectively.

Derivatives of Standard Trigonometric Functions

d/dx sin-1(x) = cos(x)

d/dx cos-1(x) = -sin(x)

d/dx tan-1(x) = sec2(x))

d/dx cot-1(x) = -csc2(x)

d/dx sec-1(x) = sec(x) tan(x)

d/dx csc-1(x) = -csc(x) cot(x)

Derivatives of Standard Inverse Trigonometric Functions

d/dx sin(x) = 1 / sqrt(1 - x2)

d/dx cos(x) = -1 / sqrt(1 - x2)

d/dx tan(x) = 1 / (1 + x2)

d/dx cot(x) = -1 / (1 + x2)

d/dx sec(x) = 1 / (x * sqrt(x2 - 1))

d/dx csc(x) = -1 / (x * sqrt(x2 - 1))


Applications of Derivatives

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One of the most important applications of derivatives is in optimization problems. Given a function, we can use calculus to find the maximum or minimum value of the function. This can be used to optimize different variables, such as profit or cost.

Rates of change: Derivatives can be used to measure the rate of change of a variable with respect to another variable.

Curve sketching: Derivatives can be used to sketch the graph of a function. By finding the derivative of a function, we can determine its critical points, inflection points, and other features that help us understand the behavior of the function.

Tangent lines and linear approximations: Derivatives can be used to find the equation of a tangent line to a curve at a given point. Derivatives can also be used to make linear approximations to a function, which can be used to approximate the value of the function at a point.

Related rates: Derivatives can be used to solve related rates problems, which involve finding the rate of change of one variable with respect to another variable. 

Read Also: Application of Derivatives


Things to Remember

  • The derivative of a function can be found using the limit definition or using differentiation formulas.
  • Differentiation formulas include the power rule, product rule, quotient rule, chain rule, and rules for differentiating trigonometric and inverse trigonometric functions.
  • Special cases, such as absolute value and logarithmic functions, require different techniques for differentiation.
  • Higher order differentiation involves taking the derivative of a function multiple times.
  • Partial differentiation involves taking the derivative of a multivariable function with respect to one variable while treating the others as constants.

Sample Questions

Ques. Find the derivative of the function f(x) = 3x2 + 2x + 1. (3 marks)

Ans: To find the derivative of f(x), we take the derivative of each term:

f'(x) = d/dx (3x2) + d/dx (2x) + d/dx (1)

= 6x + 2 + 0

= 6x + 2

Therefore, the derivative of f(x) is 6x + 2.

Ques. Find the derivative of the function g(x) = sin(2x) + cos(x). (3 marks)

Ans: To find the derivative of g(x), we use the sum rule and the chain rule:

g'(x) = d/dx (sin(2x)) + d/dx (cos(x))

= 2cos(2x) - sin(x)

Therefore, the derivative of g(x) is 2cos(2x) - sin(x).

Ques. Find the derivative of the function h(x) = ln(x2 + 1). (2 marks)

Ans: To find the derivative of h(x), we use the chain rule:

h'(x) = (1 / (x2 + 1)) * d/dx (x2 + 1)

= (2x / (x2 + 1))

Therefore, the derivative of h(x) is 2x / (x2 + 1).

Ques. Find the equation of the tangent line to the curve y = x2 - 2x + 3 at the point (2, 3). (5 marks)

Ans: To find the equation of the tangent line, we need to find the derivative of y and evaluate it at x = 2:

y' = d/dx (x2 - 2x + 3)

= 2x - 2

y'(2) = 2(2) - 2 = 2

So the slope of the tangent line is 2. To find the y-intercept, we use the point-slope form of the equation:

y - 3 = 2(x - 2)

y - 3 = 2x - 4

y = 2x - 1

Therefore, the equation of the tangent line is y = 2x - 1.

Ques. Find the partial derivative of the function f(x, y) = x2 y + x y2 with respect to x. (2 marks)

Ans: To find the partial derivative of f(x, y) with respect to x, we treat y as a constant and take the derivative of x:

∂f/∂x = d/dx (x2 y + x y2)

= 2xy + y2

Therefore, the partial derivative of f(x, y) with respect to x is 2xy + y2.

Ques. Find the derivative of the function f(x) = 3x4 - 5x3 + 2x2 - 7x + 1. (1 mark)

Ans: To find the derivative of the given function, we need to apply the power rule and the constant multiple rules. Using these rules, we get:

f'(x) = 12x3 - 15x2 + 4x - 7.

Ques. Find the derivative of the function f(x) = (x3 + 2x2 - 3x + 1)/(x2 - 1). (3 marks)

Ans: To find the derivative of the given function, we need to use the quotient rule. Using this rule, we get:

f'(x) = [(3x2 + 4x - 3)(x2 - 1) - (x3 + 2x2 - 3x + 1)(2x)]/(x2 - 1)2

Simplifying this expression, we get:

f'(x) = (x4 - 5x2 + 4)/(x2 - 1)2.

Ques. Find the derivative of the function f(x) = e(2x)sin(3x). (2 marks)

Ans: To find the derivative of the given function, we need to use the product rule and the chain rule. Using these rules, we get:

f'(x) = 2e(2x)sin(3x) + 3e(2x)cos(3x).

Ques. Find the second derivative of the function f(x) = x- 2x2 + x.(3 marks)

Ans. To find the second derivative of the given function, we first need to find its first derivative using the power rule and the constant multiple rule:

f'(x) = 3x2 - 4x + 1

Now, to find the second derivative, we differentiate f'(x) using the same rules:

f''(x) = 6x - 4.

Ques. Find the derivative of the function f(x) = ln(x2 - 4x + 5). (3 marks)

Ans: Using the chain rule and the power rule, we have:

f'(x) = d/dx[ln(x2 - 4x + 5)]

= 1/(x2 - 4x + 5) * d/dx[(x2 - 4x + 5)]

= 1/(x2 - 4x + 5) * (2x - 4)

= (2x - 4)/(x2 - 4x + 5)

Therefore, the derivative of f(x) is (2x - 4)/(x2 - 4x + 5).

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CBSE CLASS XII Related Questions

  • 1.
    Find a point on the line \( \frac{x - 2}{3} = \frac{1 - y}{2} = \frac{z - 3}{2} \) at a distance of \( \sqrt{2} \) units from the point \( (1, 2, 3) \).


      • 2.

        Find:
        Let \(A=[a_{ij}]\) be a \(2\times2\) matrix whose elements are given by \[ a_{ij}=\frac{(2i-j)^2}{3} \] Find the transpose matrix \(A'\).

          • \(\begin{bmatrix} \frac{1}{3} & 3 \\ 0 & \frac{4}{3} \end{bmatrix}\)
          • \(\begin{bmatrix} \frac{1}{3} & 0 \\ 3 & \frac{4}{3} \end{bmatrix}\)
          • \(\begin{bmatrix} \frac{4}{3} & 3 \\ 1 & 0 \end{bmatrix}\)
          • \(\begin{bmatrix} \frac{4}{3} & 0 1 & \frac{3}{3} \end{bmatrix}\)

        • 3.

          A carpenter needs to design a wooden box in the shape of a cuboid such that the sum of its length and breadth is 3 cm more than its height. Twice of its length, thrice of its breadth and its height add up to 10 cm. Its breadth added to 7 times its height is 1 cm less than 3 times its length. 


            • 4.
              Find the vector and cartesian equations of the line passing through the point of intersection of the lines \( \vec{r} = (\hat{i} + \hat{j} - \hat{k}) + \lambda(3\hat{i} - \hat{j}) \) and \( \vec{r} = (4\hat{i} - \hat{k}) + \mu(2\hat{i} + 3\hat{k}) \) and parallel to the line \( \frac{x - 1}{-2} = \frac{7 - y}{-3} = z \).


                • 5.

                  An NGO organises a charity event in which they decide to distribute woollen caps to protect children from winter. The caps to be distributed are in three separate boxes, Box I has 30 red caps, Box II has 20 red and 10 green caps, and Box III has 30 green caps. The probability that a Box i is selected and a cap picked out is i/6, where i = 1, 2, 3.  
                  Based on the above information, answer the following questions :


                    • 6.

                      At a birthday party, children are being served orange juice in conical cups, as shown in the figure. 


                      Each cup is 15 cm deep and has a radius 5 cm. The juice is being poured into this cup at a rate of 0·1 cm3/s.
                      On the basis of the above information, answer the following questions :

                        CBSE CLASS XII Previous Year Papers

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