Geometry Formulas

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Jasmine Grover

Education Journalist | Study Abroad Lead

Geometry is a branch of mathematics that deals with the study of shapes, sizes, positions, and the properties of space. It is a fundamental subject that is used in many fields such as architecture, engineering, physics, and computer graphics. 

  • Geometry formulas are essential tools that enable mathematicians and students to solve problems involving lines, angles, triangles, circles, and other shapes. 
  • These formulas provide a concise and systematic way to express the relationships between various geometric entities and enable us to calculate their measurements accurately. 
  • In this way, they are the foundation upon which geometry rests and are indispensable for understanding the principles of the subject.

Key Terms: Geometry, Square, Rectangle, Cube, Cuboid, Triangle, Area, Perimeter, Height, Base, Quadrilateral, Shapes


Basic Geometric Shapes and Formulas

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Geometry is all about shapes and their properties. In class 9, students learn about basic geometric shapes such as points, lines, angles, and planes. They also learn about triangles, quadrilaterals, and circles. 

  • Square

A square is a four-sided polygon with all sides equal in length and all angles equal to 90 degrees. The area of a square is calculated by multiplying the length of one side by itself, and the perimeter is calculated by adding the length of all four sides. The diagonals of a square are lines that connect opposite vertices. The length of a diagonal can be calculated using the Pythagorean theorem.

Square

Square

  • Area: A = s2 
  • Perimeter: P = 4s 
  • Diagonal: d = s√2, where s is the length of one side

  • Rectangle

A rectangle is a four-sided polygon with opposite sides equal in length and all angles equal to 90 degrees. The area of a rectangle is calculated by multiplying the length and width, and the perimeter is calculated by adding the length of all four sides. The diagonals of a rectangle are the lines that connect opposite vertices. The length of a diagonal can be calculated using the Pythagorean theorem.

Rectangle

Rectangle

  • Area: A = l x w 
  • Perimeter: P = 2l + 2w 
  • Diagonal: d = √(l2 + w2), where l is the length and w is the width

  • Triangle

A triangle is a three-sided polygon. The area of a triangle is calculated by multiplying the base and height and dividing the result by two, and the perimeter is calculated by adding the length of all three sides.

Triangle

Triangle

  • Area: A = 1/2bh (where b is the base and h is the height)
  • Perimeter: P = a + b + c (where a, b, and c are the lengths of the three sides)

  • Circle

A circle is a two-dimensional shape consisting of points that are equidistant from a center point. The area of a circle is calculated by multiplying pi (π) by the radius squared, and the circumference (perimeter) is calculated by multiplying the diameter by pi.

Circle

Circle

  • Area: A = πr2 (where r is the radius)
  • Circumference: C = 2πr (where r is the radius) or C = πd (where d is the diameter)
  • Diameter = 2r 

Geometry Formulas for Quadrilaterals

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A quadrilateral is a geometric shape that has four sides and four angles. The sum of the interior angles of a quadrilateral is always 360 degrees.

  • Parallelogram

A parallelogram is a four-sided polygon with opposite sides parallel to each other. The area of a parallelogram is calculated by multiplying the base and height, and the perimeter is calculated by adding the length of all four sides. The diagonals of a parallelogram can be calculated using the Pythagorean theorem.

Parallelogram

Parallelogram

  • Area: A = bh (where b is the base and h is the height)
  • Perimeter: P = 2(a + b) (where a and b are the lengths of adjacent sides)
  • Diagonal of a Parallelogram: d = √(a2 + b2 + 2abcos(θ)) (where a and b are the lengths of adjacent sides and θ is the angle between them)

  • Trapezoid

A trapezoid is a quadrilateral with one pair of parallel sides. The area of a trapezoid is calculated by multiplying the average of the parallel sides (also known as the median) by the height, and the perimeter is calculated by adding the length of all four sides.

Trapezoid

Trapezoid

  • Area: A = (a + b)h/2 (where a and b are the lengths of the parallel sides and h is the height)
  • Perimeter: P = a + b + c + d (where a and b are the lengths of the parallel sides, and c and d are the lengths of the non-parallel sides)

  • Rhombus

A rhombus is a quadrilateral with all sides equal in length. The area of a rhombus is calculated by multiplying the length of one diagonal by the length of the other diagonal, and dividing the result by two. The perimeter is calculated by adding the length of all four sides. The diagonals of a rhombus are perpendicular bisectors of each other, meaning they intersect at a 90-degree angle and bisect each other. This means that each diagonal divides the rhombus into two congruent right triangles, which can be used to find the length of the diagonals.

Rhombus

Rhombus

  • Area: A = (d1 x d2)/2 (where d1 and d2 are the lengths of the diagonals)
  • Perimeter: P = 4s (where s is the length of one side)
  • Length of Diagonals: d1 = 2asin(θ/2) and d2 = 2acos(θ/2) (where a is the length of one side and θ is the measure of one angle)

Right Triangles and Pythagorean Theorem

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Right triangles are triangles with one angle measuring 90 degrees, also known as a right angle. They have some unique properties that make them important in mathematics and real-world applications. One of the most fundamental and useful tools for working with right triangles is the Pythagorean theorem.

Right triangles

Right Triangles

Similar to triangle, the area of a right triangle is calculated by multiplying the base and height and dividing the result by two, and the perimeter is calculated by adding the length of all three sides.

  • Area: A = ½ bh (where b is the base and h is the height)
  • Perimeter: P = a + b + c (where a, b, and c are the lengths of the three sides)

The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. This theorem can be written as an equation:

a2 + b2 = c2

where a and b are the lengths of the two legs (the sides adjacent to the right angle) and c is the length of the hypotenuse.

This theorem can be used to find the length of any side of a right triangle, as long as the lengths of the other two sides are known. It can also be used to determine if a triangle is a right triangle, by checking if the lengths of its sides satisfy the equation a2 + b2 = c2

Heron's formula

Heron's formula is a formula used to calculate the area of a triangle when the lengths of all three sides are known. The formula is named after the ancient Greek mathematician Hero of Alexandria. Here's the formula:

Let a, b, and c be the lengths of the three sides of a triangle. Then the area of the triangle is given by:

A = √[s(s-a)(s-b)(s-c)]

where s is the semi-perimeter of the triangle, which is half the perimeter, or:

s = (a + b + c)/2

Heron's formula is useful when you know the lengths of all three sides of a triangle but cannot determine its height, or when other methods of calculating the area are too complicated. It is commonly used in geometry and can be applied to any type of triangle, whether it is equilateral, isosceles, or scalene.


Arc and Sector of a Circle Formula

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A circle is a two-dimensional shape that is defined as a set of points that are equidistant from a fixed point called the center of the circle.

Arc and Sector of a Circle Formula

Arc and Sector of a Circle Formula

  • Arc of a Circle

An arc of a circle is a portion of the circumference of the circle. The length of an arc can be calculated using the following formula:

Arc Length = (angle θ/360°) x 2πr

where θ is the central angle of the arc (measured in degrees), r is the radius of the circle, and 2πr is the circumference of the circle.

  • Sector of a Circle

A sector of a circle is a region bounded by two radii and an arc. The area of a sector can be calculated using the following formula:

Sector Area = (angle θ/360°) x πr2

where θ is the central angle of the sector (measured in degrees), r is the radius of the circle, and πr2 is the area of the circle.

Additionally, the length of the arc that forms the sector can be found using the arc length formula mentioned above.


Congruence and Similarity

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Congruence and similarity are two important concepts in geometry that describe the relationship between different geometric shapes.

Congruence refers to the property of having the same shape and size. Two geometric shapes are said to be congruent if they have the same size and shape, meaning that all corresponding angles and sides are equal. Congruent shapes can be moved, rotated, or flipped without changing their size or shape. Congruence is denoted by the symbol "≅" (congruent sign).

Congruent Triangle

Congruent Triangles

To determine whether two shapes are congruent or similar, one can use various methods such as the angle-angle (AA), side-angle-side (SAS), and side-side-side (SSS) criteria. These criteria are based on the corresponding angles and sides of the two shapes and can be used to show that the shapes are either congruent or similar.

On the other hand, similarity refers to the property of having the same shape, but not necessarily the same size. Two geometric shapes are said to be similar if they have the same shape, meaning that all corresponding angles are equal, but their corresponding sides may be different lengths. Similar shapes can be scaled up or down uniformly, while still maintaining their shape. The similarity is denoted by the symbol "∼" (tilde sign).

Similarity

Similarity


Geometry Formulas of Three-Dimensional Shapes

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Three-dimensional shapes, also known as 3D shapes or solids, are objects that have length, width, and height or depth. 

  • Cube

A cube is a three-dimensional shape with six square faces of equal size.

Cube

Cube

Its formulas are:

  • Volume: V = s3
  • Surface area: A = 6s2
  • Diagonal: d = s√3, where s is the length of any edge of the cube

  • Cuboid

A cuboid/rectangular prism is a three-dimensional shape with six rectangular faces. 

Cuboid

Cuboid

Its formulas are:

  • Volume: V = lwh
  • Surface area: A = 2lw + 2lh + 2wh
  • Diagonal: d = √(l2 + w2 + h2), where l is the length, w is the width, and h is the height of the prism.

  • Sphere

A sphere is a three-dimensional shape with a curved surface. 

Sphere

Sphere

Its formulas are:

  • Volume: V = (4/3)πr3
  • Surface area: A = 4πr2
  • Diameter: 2r, where r is the radius of the sphere.

  • Cylinder

A cylinder is a three-dimensional shape with a circular base and a curved surface.

Cylinder

Cylinder

Its formulas are:

  • Volume: V = πr2h
  • Surface area: A = 2πr2 + 2πrh
  • Curved surface area: Acurved = 2πrh
  • Base: The base of the cylinder is a circle with radius r.
  • Height: The height of the cylinder is h.

  • Cone

A cone is a three-dimensional shape with a circular base and a curved surface that tapers to a point.

Cone

Cone

Its formulas are:

  • Volume: V = (1/3)πr2h
  • Surface area: A = πr2+ πr√(r2+ h2)
  • Curved surface area: A_curved = πr√(r2+ h2),
  • Slant height: l = √(r2+ h2
  • Base: The base of the cone is a circle with radius r.
  • Height: The height of the cone is h.

Co-ordinate Geometry Formulas

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The important formulas in coordinate geometry are as follows:

  • Distance Formula: The distance between two points (x1, y1) and (x2, y2) in a coordinate plane is given by:

d = √[(x2 - x1)2 + (y2 - y1)2]

  • Midpoint Formula: The midpoint between two points (x1, y1) and (x2, y2) in a coordinate plane is given by:

[(x1 + x2)/2, (y1 + y2)/2]

  • Slope Formula: The slope of a line passing through two points (x1, y1) and (x2, y2) is given by:

m = (y2 - y1)/(x2 - x1)

  • Equation of a Line: The equation of a line in slope-intercept form (y = mx + b) can be determined using the slope and the y-intercept (b). The slope (m) is given by the formula above, and the y-intercept (b) can be found using the point-slope formula:

y - y1 = m(x - x1)

  • Parallel and Perpendicular Lines: Two lines are parallel if they have the same slope, and they are perpendicular if their slopes are negative reciprocals of each other. The equation of a line parallel to a given line can be found by keeping the same slope and changing the y-intercept, while the equation of a line perpendicular to a given line can be found by taking the negative reciprocal of the slope and changing the sign.
  • Area of a Triangle: The area of a triangle formed by three points (x1, y1), (x2, y2) and (x3, y3) is given by:

A = 1/2 |x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)|

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Things to Remember

  1. Geometry is a branch of mathematics that deals with shapes, sizes, and relative positions of objects.
  2. It involves basic geometric shapes such as points, lines, angles, triangles, quadrilaterals, and circles, and important formulas and equations related to them such as perimeter, area, circumference, and diameter.
  3. Concepts such as the Herons formula, Pythagorean theorem, congruence, and similarity of triangles are also important in class 9 mathematics.
  4. Coordinate geometry is another branch of geometry that deals with the Cartesian plane and the distance and midpoint between two points.
  5. Three-dimensional shapes such as cubes, cylinders, and spheres are also taught, along with their formulas related to volume and surface area.
  6. Geometry has practical applications in fields such as engineering, architecture, and art.

Sample Questions

Ques: A triangular field has sides of length 12 m, 16 m, and 20 m. Find the area of the field. (5 marks)

Ans. We can use Heron's formula to find the area of the triangular field. Heron's formula states that the area of a triangle with sides of length a, b, and c is given by:

Area = sqrt(s(s-a)(s-b)(s-c))

where s = (a+b+c)/2 is the semi perimeter of the triangle.

Plugging in the values for the sides of the triangular field, we get:

s = (12 + 16 + 20)/2 = 24

Area = sqrt(24(24-12)(24-16)(24-20))

= sqrt(24128*4)

= 96 sq. m

Therefore, the area of the triangular field is 96 square meters.

Ques: Find the perimeter of a rectangle with a length of 10 cm and a width of 6 cm. (3 marks)

Ans: The perimeter of a rectangle is given by the formula 2(l + w), 

where l is the length and w is the width. 

Plugging in the values, we get: 

P = 2(10 + 6) = 32 cm. 

Therefore, the perimeter of the rectangle is 32 cm.

Ques: A cylindrical tank has a radius of 2 meters and a height of 5 meters. Find the volume of the tank. (Use π = 3.14) (3 marks)

Ans. The volume of a cylinder is given by the formula V = πr2h, 

where r is the radius and h is the height. 

Plugging in the values, we get: 

V = 3.14 x 22 x 5 = 62.8 cubic meters. 

Therefore, the volume of the cylindrical tank is 62.8 cubic meters.

Ques: A triangular pyramid has a base with sides of length 4 cm, 5 cm, and 6 cm, and a height of 8 cm. Find the volume of the pyramid. (5 marks)

Ans: The volume of a pyramid is given by the formula V = (1/3)Bh, 

where B is the area of the base and h is the height. 

First, we need to find the area of the base using Heron's formula:

s = (4 + 5 + 6)/2 = 7.5

Area of base = sqrt(7.5(7.5-4)(7.5-5)(7.5-6)) = sqrt(90) = 9.49 sq. cm

Now we can plug in the values to get the volume:

V = (1/3) x 9.49 x 8 = 25.3 cubic cm

Therefore, the volume of the triangular pyramid is 25.3 cubic centimeters.

Ques: A rectangular prism has a length of 10 cm, a width of 6 cm, and a height of 4 cm. Find the surface area of the prism. (3 marks)

Ans: The surface area of a rectangular prism is given by the formula SA = 2lw + 2lh + 2wh, where l is the length, w is the width, and h is the height. 

Plugging in the values, we get:

SA = 2(10 x 6) + 2(10 x 4) + 2(6 x 4) = 220 sq. cm. 

Therefore, the surface area of the rectangular prism is 220 square centimetres.

Ques: Find the distance between the points (4, 5) and (-2, -3) on the Cartesian plane. (3 marks)

Ans. The distance between two points (x1, y1) and (x2, y2) is given by the formula d = sqrt((x– x1)2 + (y2 – y1)2).

Plugging in the values, we get: 

d = sqrt(( – 2  – 4)2 + ( – 3 – 5)2

= sqrt (64 + 64) = sqrt(128) 

= 11.31. 

Therefore, the distance between points (4, 5) and (-2, -3) is 11.31 units.

Ques: Find the area of a trapezoid with a height of 8 cm, a shorter base of 5 cm, and a longer base of 10 cm. (3 marks)

Ans: The area of a trapezoid is given by the formula A = (h/2)(b1 + b2),

where h is the height, b1 is the shorter base, and b2 is the longer base. 

Plugging in the values, we get: 

A = (8/2)(5 + 10) 

= 60 sq. cm. 

Therefore, the area of the trapezoid is 60 square centimetres.

Ques. A square pyramid has a base with sides of a length of 10 cm and a height of 12 cm. Find the volume of the pyramid. (5 marks)

Ans. The volume of a pyramid is given by the formula V = (1/3)Bh, 

where B is the area of the base and h is the height. 

For a square pyramid, the area of the base is given by B = s2

where s is the length of a side. 

Plugging in the values, we get: 

B = 102 = 100 sq. cm. 

Now we can plug in the values to get the volume: V = (1/3) x 100 x 12 = 400 cubic cm. Therefore, the volume of the square pyramid is 400 cubic centimeters.

Ques: Find the length of a diagonal of a rectangle with length 8 cm and width 6 cm. (3 marks)

Ans. The length of a diagonal of a rectangle is given by the formula 

d = sqrt(l2 + w2), 

where l is the length and w is the width. 

Plugging in the values, we get: 

d = sqrt(82 + 62

= sqrt(100) 

= 10 cm. 

Therefore, the length of the diagonal is 10 cm.

Ques. A rectangular prism has a length of 12 cm, a width of 5 cm, and a height of 8 cm. Find the volume of the prism. (3 marks)

Ans: The volume of a rectangular prism is given by the formula V = lwh, 

where l is the length, w is the width, and h is the height.

Plugging in the values, we get: 

V = 12 x 5 x 8 = 480 cubic cm. 

Therefore, the volume of the rectangular prism is 480 cubic centimeters.

Ques: Find the length of the hypotenuse of a right triangle with legs of length 5 cm and 12 cm. (3 marks)

Ans. The length of the hypotenuse of a right triangle is given by the Pythagorean theorem, which states that c2 = a2 + b2 

where c is the length of the hypotenuse, and a and b are the lengths of the legs. 

Plugging in the values, we get: 

c2 = 52 + 122

= 169. 

Taking the square root of both sides, 

we get: c = sqrt(169) = 13 cm. 

Therefore, the length of the hypotenuse is 13 cm.

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CBSE X Related Questions

  • 1.
    The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

      • 0
      • 1
      • 3
      • 2

    • 2.
      The natural number 1 is :

        • a prime number.
        • a composite number.
        • prime as well as composite.
        • neither prime nor composite.

      • 3.
        Two water taps together can fill a tank in $8\frac{8}{9}$ hours. The tap of larger diameter takes 4 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.


          • 4.
            If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then

              • \( \frac{a_1}{a_2} \neq \frac{b_1}{b_2} \)
              • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
              • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} \)
              • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)

            • 5.
              \(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

                • \(\frac{21}{4} \text{ cm}\)
                • \(\frac{28}{3} \text{ cm}\)
                • \(\frac{12}{7} \text{ cm}\)
                • \(5.5 \text{ cm}\)

              • 6.
                Prove that :
                \(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).

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