NCERT Solutions For Class 10 Maths Chapter 4: Quadratic Equations

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Jasmine Grover

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The NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations are given in this article. Quadratic Equations are polynomial equations with the degree of the equation equal to 2 in one variable shape. For example:  f(x) = ax2 + bx + c in which a, b, c, ∈ r and a ≠ 0. The values that fulfil a given quadratic equation are called roots and each equation has at least 2 roots. 

Class 10 Maths Chapter 4 Quadratic Equations belongs to Unit 2 Algebra which has a weightage of 20 marks in the CBSE Class 10 Maths Examination. Questions related to finding the nature of roots of Quadratic Equation and Quadratic Equations Formula are often asked in the examination.

Download PDF: NCERT Solutions for Class Class 10 Mathematics Chapter 4


NCERT Solutions for Class 10 Mathematics Chapter 4

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Important Topics in Class 10 Maths Chapter 4

  • A polynomial of the form ax2 + bx + c, where a, b and c are real numbers and a is not equal to 0 is known as a quadratic polynomial. 
Any equation of the form p(x) = c, where p(x) is any polynomial of degree 2 and c is a constant, can be identified as a quadratic equation.
  • The roots of quadratic equation are the values of x for which a quadratic equation is satisfied.

A quadratic equation can either have 2 distinct real roots, 2 equal roots or the real roots for the equation may not exist.
  • Quadratic Formula can be used to directly find the roots of a quadratic equation from its standard form.

For the quadratic equation ax2 + bx + c = 0, x = [-b ± √(b2-4ac)]/2a

  • Discriminant of the Quadratic Equation – For a quadratic equation ax2 + bx + c = 0, the expression b2 − 4ac is known as the discriminant, (denoted by D).

The discriminant determines the nature of the roots of the quadratic equation based on its coefficients.

  • Based on the discriminant value, D = b2 − 4ac, the quadratic equation roots can be of three types.

Case 1: If D > 0, the equation has two distinct real roots.

Case 2: If D = 0, the equation has two equal real roots.

Case 3: If D < 0, the equation has no real roots.


NCERT Solutions For Class 10 Maths Chapter 4 Exercises:

The detailed solutions for all the NCERT Solutions for Quadratic Equations under different exercises are as follows:


Quadratic Equations – Related Topics:

CBSE Class 10 Maths Study Guides:

CBSE X Related Questions

  • 1.
    If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).


      • 2.
        D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.


          • 3.
            A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.


              • 4.
                If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

                  • \(4 \text{ cm}\)
                  • \(4\sqrt{2} \text{ cm}\)
                  • \(8 \text{ cm}\)
                  • \(2\sqrt{2} \text{ cm}\)

                • 5.
                  PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.


                    • 6.
                      In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

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