NCERT Solutions for Class 10 Maths Chapter 4 Exercise 4.1

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Jasmine Grover

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NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Exercise 4.1 is provided in this article. Class 10 Maths Chapter 4 is an important chapter of Unit 2 Algebra which has a weightage of 20 marks in the CBSE Class 10 Maths Examination.

Download PDF: NCERT Solutions for Class 10 Maths Chapter 4 Exercise 4.1

Check out the solutions of Class 10 Maths NCERT solutions chapter 4 Quadratic Equations 4.1

Read More: NCERT Solutions For Class 10 Maths Quadratic Equations

Check out other exercise solutions of Class 10 Maths Chapter 4

Class 10 Chapter 4 Topics:

CBSE Class 10 Maths Study Guides:

CBSE X Related Questions

  • 1.
    The natural number 1 is :

      • a prime number.
      • a composite number.
      • prime as well as composite.
      • neither prime nor composite.

    • 2.
      In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.


        • 3.
          Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)


            • 4.
              If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).


                • 5.
                  There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

                    • 144
                    • 2
                    • 420
                    • 272

                  • 6.
                    In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

                      • \( 130^\circ \)
                      • \( 50^\circ \)
                      • \( 120^\circ \)
                      • \( 90^\circ \)

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